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topjm [15]
3 years ago
12

What pressure will be needed to lwave the vloume of 77.4L ay helium at 98.OK pa to a vloume of 60.0L

Chemistry
1 answer:
Mkey [24]3 years ago
7 0
89.O K that should help
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Hellllpppppppp helppppppppp
mixas84 [53]

Answer :

Charles's Law : It is defined as the volume is directly proportional to the temperature of the gas at constant pressure and number of moles.

Mathematically,

V\propto T

                                Boiling water bath        Cool bath 1       Cool bath 2

Temperature (⁰C)                  99                              17                       2

Temperature (K)(T)    273+99=372             273+17=290      273+2=275

Volume of water                  0.0                             27.0                34.0

in cool flask (mL)

Volume of water=              135.8                           135.8               135.8

Air in flask (mL)

Volume of air                    135.8                           108.8               101.8

in cool flask (V)

\frac{V}{T}                                \frac{135.8}{372}=0.365             \frac{108.8}{290}=0.375         \frac{101.8}{275}=0.370

The graph volume versus temperature for a gas is shown below.

3 0
3 years ago
Which structures join with the cell’s membrane during exocytosis?
erma4kov [3.2K]

Answer:Exocytosis is also used to integrate new proteins into the cell membrane. In this process, the new protein is formed inside the cell, and migrates to phospholipid bilayer of the vesicle. The vesicle, containing the new protein as a part of the phospholipid bilayer, fuses with the cell membrane.

Explanation:

8 0
3 years ago
The ksp of lead iodide is 7.1 × 10-9. a chemical engineer adds 0.0025 mol of ki to a solution of 0.00004 mol pb(no3)2 in 500 ml
inn [45]
Answer is: n<span>o, because the ion product is less than the Ksp of lead iodide. </span>

Chemical dissociation 1: KI(s) → K⁺(aq) + I⁻(aq).
Chemical dissociation 2: Pb(NO₃)₂(s) → Pb²⁺(aq) + 2NO₃⁻(aq).
Chemical reaction: Pb²⁺(aq) + 2I⁻(aq) → PbI₂(s).
Ksp(PbI₂) = 7.1·10⁻⁹.
V = 500 mL ÷ 1000 mL/L = 0.5 L.
c(KI) = c(I⁻) = 0.0025 mol ÷ 0.5 L.
c(I⁻) = 0.005 M.
c(Pb(NO₃)₂) = c(Pb²⁺) = 0.00004 mol ÷ 0.5 L.
c(Pb²⁺) = 0.00008 M.
Q = c(Pb²⁺) · c(I⁻)².
Q = 8·10⁻⁵ M · (5·10⁻³ M)².
Q = 2·10⁻⁹; <span> the ion product.</span>

8 0
3 years ago
The screenshts below
ICE Princess25 [194]

Answer:

yes so for example one

Explanation:

yeah so

7 0
2 years ago
Which organisms in the food web shown compete for the same food source in this environment?
11111nata11111 [884]

Answer:

there is no photo

Explanation:

3 0
3 years ago
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