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dybincka [34]
3 years ago
10

Which element is always found in impure form naturally

Chemistry
2 answers:
harkovskaia [24]3 years ago
8 0
The answer is C. Aluminium since it is highly reactive
S_A_V [24]3 years ago
7 0
C. Aluminium is the answer
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1. B.10 mol/l

2. D.

3.A.

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In a position time graph, a steep slope indicates _____.
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Im pretty positive its A , hope this helps!
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20.0 mL of 0.06 M HCl (in a flask) is titrated with 0.04 M NaOH (in a burette). How many milliliters of NaOH needs to be used to
Liula [17]
<span>0.0200 L X 0.06 mol/L HCl = 1.2X10^-3 mol HCl
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What is the source of solar energy? electricity . solar panels the sun None of the above <br>​
stepan [7]

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Ethanol melts at -114 degree C. The enthalpy of fusion
Brut [27]

Answer: The heat required is 6.88 kJ.

Explanation:

The conversions involved in this process are :

(1):ethanol(s)(-135^0C)\rightarrow ethanol(s)(-114^0C)\\\\(2):ethanol(s)(-114^0C)\rightarrow ethanol(l)(-114^0C)\\\\(3):ethanol(l)(-114^0C)\rightarrow ethanol(l)(-50^0C)

Now we have to calculate the enthalpy change.

\Delta H=[m\times c_{p,s}\times (T_{final}-T_{initial})]+n\times \Delta H_{fusion}+[m\times c_{p,l}\times (T_{final}-T_{initial})]+n\times \Delta H_{vap}+[m\times c_{p,g}\times (T_{final}-T_{initial})]

where,

\Delta H = enthalpy change = ?

m = mass of ethanol = 25.0 g

c_{p,s} = specific heat of solid ethanol= 0.97 J/gK

c_{p,l} = specific heat of liquid ethanol = 2.31 J/gK

n = number of moles of ethanol = \frac{\text{Mass of ethanol}}{\text{Molar mass of ethanol}}=\frac{25.0g}{46g/mole}=0.543mole

\Delta H_{fusion} = enthalpy change for fusion = 5.02 KJ/mole = 5020 J/mole

T_{final}-T_{initial}=\Delta T = change in temperature

The value of change in temperature always same in Kelvin and degree Celsius.

Now put all the given values in the above expression, we get

\Delta H=[25.0 g\times 0.97J/gK\times (-114-(-135)K]+0.534mole\times 5020J/mole+[25.0g\times 2.31J/gK\times (-50-(-114))K]

\Delta H=6885.93J=6.88kJ     (1 KJ = 1000 J)

Therefore, the heat required is 6.88 kJ

3 0
2 years ago
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