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love history [14]
3 years ago
13

Cosmologists are scientists who study stars, galaxies, black holes, and other objects in the universe. In order to study the bil

lions and billions of stars, cosmologists use highly advanced telescopes and create computer models to trace the stars’ motion.
What is one type of limitation that requires cosmologists to use these telescopes?

A.money
B.time
C.the size of the system
D.ethical concerns
Physics
2 answers:
juin [17]3 years ago
5 0

Answer:

c

Explanation:

:) hey

algol [13]3 years ago
3 0

Answer:

a

idkdidkdidkdkkdhdksijsnansjnshejdhjsnnebdhhdbsbbshshhsnsjshs

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A helicopter’s speed increases from 30 m/s to 40 m/s in 5 seconds.
Mandarinka [93]
7 m over s² or 7ms⁻¹
5 0
3 years ago
A 6 kilogram block in outer space is moving at -100 m/s (to the left). It suddenly experiences three forces as shown below (in t
Blizzard [7]

Answer:

x = 1474.9 [m]

Explanation:

To solve this problem we must use Newton's second law, which tells us that the sum of forces must be equal to the product of mass by acceleration.

We must understand that when forces are applied on the body, they tend to slow the body down to stop it.

So as the body continues to move to the left, it is slowing down. Therefore we must calculate this deceleration value using Newton's second law. We must perform a sum of forces on the x-axis equal to the product of mass by acceleration. With leftward movement as negative and rightward forces as positive.

ΣF = m*a

10 +12*sin(60)= - 6*a\\a = - 3.39[m/s^{2}]

Now using the following equation of kinematics, we can calculate the distance of the block, before stopping completely. The initial speed must be 100 [m/s].

v_{f}^{2} =v_{o}^{2}-2*a*x

where:

Vf = final velocity = 0 (the block stops)

Vo = initial velocity = 100 [m/s]

a = - 3.39 [m/s²]

x = displacement [m]

0 = 100^{2}-2*3.39*x\\x=\frac{10000}{2*3.39}\\x=1474.9[m]

4 0
3 years ago
A sphere of radius 0.081029 m is made of aluminum. It is submerged in flowing water with a temperature of 25 °C that results in
Dimas [21]

Answer:

its surface temperature = 54.84 ° C

Explanation:

The density of aluminium (\rho) = 2700 kg/m ³

Heat capacity ( c_p) = 897 J/Kg.K

radius of the sphere (r) = 0.081029 m

T \infty = 25 °C

T_i = 124.978  °C

time (t) = 767.276 s

Using the formula :

\frac{T-T_{ \infty} }{T_i - T_{\infty}}= e^{-\frac{hA}{\rho V c_p}}*t

where.

\frac{V}{A}= \frac{r}{3}

Replacing our values ;we have:

\frac{T-25 }{124.978 - 25}= e^{-\frac{-103.067*3}{2700*897*0.081029}}*767.276

\frac{T-25 }{124.978 - 25}= e^{{-0.001576}*767.276

\frac{T-25 }{124.978 - 25}= e^{-1.209}

\frac{T-25 }{99.978}= 0.2985

{T-25 }= 0.2985*{99.978}

{T-25 }= 29.843433

{T= 29.843433+25 }

{T= 54.843433

T ≅ 54.84 ° C

Therefore, its surface temperature = 54.84 ° C

6 0
4 years ago
Describe how charge is transferred from the ruler to the metal rod.
spin [16.1K]
When the ruler is broughı near the inetal knob, it repels electrons in the metal. Electrons move away froni the ruler and down the metal rod. The knob now has a positive charge. The thin pieces of metal foil at the bottom of the metal rod now have a negative charge.
3 0
3 years ago
Read 2 more answers
A heavy piece of hanging sculpture is suspended by a 90 cm-long, 5.0 g steel wire. When the wind blows hard, the wire hums at it
kupik [55]

Answer: The mass of the sculpture is 11.8kg

Explanation:

Using the equation of fundamental frequency of a taut string.

f = (1/2L)*√(T/μ) .... (Eqn1)

Where

f= frequency in Hertz =80Hz

T = Tension in the string = Mg

M represent the mass of the substance (sculpture) =?

g= 9.8m/s^2

L= Length of the string=90cm=0.9m

μ= mass density = mass of string /Length of string

mass of string =5g=0.005kg

L=0.9m

μ=0.005/0.9 = 0.0056kg/m

Using (Eqn1)

80= 1/(2*0.9) √(T/0.0056)

144= √(T/0.0056)

Square both sides

20736= T/0.0056

T= 116.12N

Recall that T =Mg

116.12= M * 9.8

M=116.12/9.8

M= 11.8kg

Therefore the mass of the sculpture is 11.8kg

4 0
3 years ago
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