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GuDViN [60]
3 years ago
11

A piece of tape is pulled from a spool and lowered toward a 120-mg scrap of paper. Only when the tape comes within 8.0 mm is the

electric force magnitude great enough to overcome the gravitational force exerted by Earth on the scrap and lift it.
Physics
1 answer:
Anton [14]3 years ago
6 0

Answer:

1.176\times 10^{-3} N

Upward

Explanation:

We are given that

Mass of scarp paper,m=120 mg=120\times 10^{-6}kg

1mg=10^{-6} mkg

Distance,d =8 mm=8\times 10^{-3} m

Magnitude of electric force =F_E= w=mg

Where g=9.8 m/s^2

Substitute the values

F_E=120\times 10^{-6}\times 9.8

F_E=1.176\times 10^{-3} N

Gravitational force act in  downward direction.

The electric force acts in opposite direction and magnitude of electric force is equal to gravitational force.

Hence, the direction of electric force is upward.

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Answer:

The range of the bullet is 0.435 kilometers.

Explanation:

According to the problem, maximum height is equal to the range of the bullet. That is:

\Delta x = \Delta y

Where:

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\Delta y - Maximum height of the bullet, measured in meters.

By the Principle of Energy Conservation, gravitational potential energy reaches its maximum at the expense of the initial kinetic energy. That is to say:

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Where:

K_{1} - Kinetic energy at point 1, measured in joules.

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The maximum height is now cleared:

K_{1} = m\cdot g \cdot \Delta y

\Delta y = \frac{K_{1}}{m\cdot g}

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