The box is at equilibrium, so the net force on the box is zero (the force of gravity on the box is equal to the force exerted up on the box by the surface on which it rests.)
To pick up the box, our upward force must be greater than the force of gravity on the box (the weight). So, we must lift up the box with a force greater than 98 newtons. :)
Answer:
The magnitude of the average frictional force on the block is 2 N.
Explanation:
Given that.
Mass of the block, m = 2 kg
Initial velocity of the block, u = 10 m/s
Distance, d = 50 m
Finally, it stops, v = 0
Let a is the acceleration of the block. It can be calculated using third equation of motion. It can be given by :
The frictional force on the block is given by the formula as :
F = ma
|F| = 2 N
So, the magnitude of the average frictional force on the block is 2 N. Hence, this is the required solution.
<u>Question:</u>
A piece of soft iron is placed in a solenoid increasing the magnetic field in an arrangement that can be switched on and off. Such a device is called
Answer
a hysteresis loop.
an electrosolenoid.
a permanent magnet.
a ferromagnet.
an electromagnet
<u>Answer:</u>
A piece of soft iron is placed in a solenoid increasing the magnetic field in an arrangement that can be switched on and off. Such a device is called an electromagnet.
<u>Explanation:</u>
When a magnet is processed by supplying electricity than it is called as electromagnet and therefore its strength can be fluctuated as dependent on amount of electricity supplied.
Here, when a iron piece is moved closer to a long coil of wire named solenoid physical interaction named electromagnetic force take place between two electrically charged particles.
This force is supplied by electromagnetic fields constructed from electric and magnetic field. This is also called as Lorentz force constituted from both electricity and magnetism. This property itself gives evidence of characteristics of material used for electromagnetism.
Answer:
Conversion tables show:
1 m = 1.09361 yds
1 Lit = .26418 gal = 1.05672 qt or 1 qt = .944632 Lit
1 lb = .45359 kg = 2.2046 Lbs / Kg
So X yds = X m * 1.09361 yds / m = 1.09361 * X yds
Likewise X Lit = X qt / 1.05672 qt/ Lit = X / 1.05672 Lit = .94632 X Lit
So X Lbs = X kg * 2.2046 Lbs / Kg = 2.2046 Lbs
Answer:
43.58 m
Explanation:
If you travel 500 m on a straight road that slopes upward at a constant angle of 5 degrees
Using trigonometry ratio
Sin 5 = opposite/hypothenus
Where the hypothenus = 500m
Opposite = height h
Sin 5 = h/500
Cross multiply
500 × sin 5 = h
h = 500 × 0.08715
h = 43.58m
Therefore, the height above the starting point is equal to 43.58m
