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Romashka [77]
2 years ago
8

On one stretch of road, any vehicle travelling faster than 25 m/s is breaking the speed limit. The detectors are placed 1.2 m ap

art. Calculate the speed of a car that takes 0.050 s to travel this distance. Is it breaking the speed limit?​
Physics
1 answer:
Nadya [2.5K]2 years ago
4 0

Answer:

Speed = 24 m/s.

No! It doesn't break the speed limit.

Explanation:

The formula we'll be using to find the car's speed:

\boxed{ \mathsf{speed =  \frac{distance}{time} }}

The detectors are placed 1.2 m apart.

==> Distance the car travels = 1.2 m

The car, it says, takes 0.050 s to travel that distance.

==> Time taken by the car to travel 1.2 m = 0.050 s

Using the formula mentioned above, let's calculate the speed of the car:

\sf{speed =  \frac{distance}{time} }

\implies \sf{speed =  \frac{1.2}{0.050} }

<em>On</em><em> </em><em>dividing</em><em> </em><em>1</em><em>2</em><em> </em><em>by</em><em> </em><em>0</em><em>.</em><em>0</em><em>5</em><em>0</em><em> </em><em>we</em><em> </em><em>obtain</em><em> </em><em>2</em><em>4</em><em>.</em>

\implies \sf{speed = 24 \: m/s }

Any car traveling with a speed that is greater than or equal to <u>2</u><u>5</u><u> </u><u>m</u><u>/</u><u>s</u> is breaking the speed limit.

And since the car in our focus is traveling at 24 m/s that is less than 25 m/s, it doesn't break the speed limit.

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Answer:

The answer to your question is: DNA.

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3 years ago
A feather is dropped on the moon from the height of 1.4m. The acceleration of gravity on the moon is 1.67ms-1. Determine the tim
Zinaida [17]

1.3s

Explanation:

Given parameters:

Height = 1.4m

Gravity on moon = 1.67ms⁻¹

Unknown:

Time for feather to fall = ?

Solution:

To solve this problem, we are going to use one of the motion equation that relates time, gravity and height.

    H = ut + \frac{1}{2} g t^{2}

Sine the body was dropped from rest, initial velocity is zero;

 H = height

  u = initial velocity

  t = time

  g = acceleration due to gravity

since u = 0;

H = \frac{1}{2} g t^{2}

 1.4 = \frac{1}{2} x 1.67 x t²

  t = 1.3s

learn more:

Gravity brainly.com/question/10934170

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8 0
3 years ago
A ball falling through the air has what?
AysviL [449]
A ball falling through the air has a mass, a density, a volume...it is facing air resistance and is being acted on by gravity...it is accelerating and gaining velocity...and it is increasing in kinetic energy.
I suppose out of all those the biggest thing the ball has in this case is ENERGY. There are two main types to focus on...

Kinetic Energy - The further the ball fall the more KE it has...until terminal velocity is reach, then KE would become constant. 
Potential Energy - Conversely to that of KE, the further the ball falls the less PE it will have. 

<em>Heat/Thermal Energy is technically also present due to the friction from the air resistance, but the transfer of energy between the air and ball is quite complex and not necessary important for basic physics.  
</em>
The question itself seem kind of vague and open ended, but I could just be viewing it the wrong way. 
Comment if you need more help! 
8 0
3 years ago
14. Three identical light bulbs are connected in series, then are disconnected and arranged in parallel. For each of the scenari
Inessa [10]
In order to make things easier to describe and explain, let's call
the resistance of each bulb 'R', and the battery voltage 'V'.

a).  In series, the total resistance is 3R.
In parallel, the total resistance is R/3.
Changing from series to parallel, the total resistance of the circuit
decreases to 1/9 of its original value.

b).  In series, the total current is  V / (3R) .
In parallel, the total current is  3V / R .
Changing from series to parallel, the total current in the circuit
increases to 9 times its original value.

c).  In series, the power dissipated by the circuit is 

                                   (V) · V/3R  =  V² / 3R .

In parallel, the power dissipated by the circuit is

                                   (V) · 3V/R  =  3V² / R .

Changing from series to parallel, the power dissipated by
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to 9 times its original value.

8 0
3 years ago
11) A sled is initially given a shove up a frictionless 35º incline. It reaches a maximum height of 2.5
Andrej [43]

Answer:

7 m/s

Explanation:

To solve this problem you must use the conservation of energy.

K1 +U1=K2+U2

That math speak for, initial kinetic energy plus initial potential energy equals final kinetic energy plus final potential energy.

The initial PE (potential energy) is 0 because it hasn't been raised in the air yet. The final KE (kinetic energy) is 0 because it isn't moving. This gives the following:

KE1= \frac{1}{2}mv^{2}}

PE2=mgh

K1=U2

\frac{1}{2} mv^{2} =mgh

Solve for v

v=\sqrt{2gh}

Input known values and you get 7 m/s.

5 0
3 years ago
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