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Romashka [77]
2 years ago
8

On one stretch of road, any vehicle travelling faster than 25 m/s is breaking the speed limit. The detectors are placed 1.2 m ap

art. Calculate the speed of a car that takes 0.050 s to travel this distance. Is it breaking the speed limit?​
Physics
1 answer:
Nadya [2.5K]2 years ago
4 0

Answer:

Speed = 24 m/s.

No! It doesn't break the speed limit.

Explanation:

The formula we'll be using to find the car's speed:

\boxed{ \mathsf{speed =  \frac{distance}{time} }}

The detectors are placed 1.2 m apart.

==> Distance the car travels = 1.2 m

The car, it says, takes 0.050 s to travel that distance.

==> Time taken by the car to travel 1.2 m = 0.050 s

Using the formula mentioned above, let's calculate the speed of the car:

\sf{speed =  \frac{distance}{time} }

\implies \sf{speed =  \frac{1.2}{0.050} }

<em>On</em><em> </em><em>dividing</em><em> </em><em>1</em><em>2</em><em> </em><em>by</em><em> </em><em>0</em><em>.</em><em>0</em><em>5</em><em>0</em><em> </em><em>we</em><em> </em><em>obtain</em><em> </em><em>2</em><em>4</em><em>.</em>

\implies \sf{speed = 24 \: m/s }

Any car traveling with a speed that is greater than or equal to <u>2</u><u>5</u><u> </u><u>m</u><u>/</u><u>s</u> is breaking the speed limit.

And since the car in our focus is traveling at 24 m/s that is less than 25 m/s, it doesn't break the speed limit.

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What is the scientific term for rocks formed from lava?
sergeinik [125]

Answer:

extrusive I'm pretty sure that's right

5 0
3 years ago
A driver in a car traveling at a speed of 50 mi/h sees a deer 50 m away on the road. Calculate the minimum constant acceleration
alisha [4.7K]

Answer:

a= - 0.79 m/s²

Explanation:

Given that

Speed ,u = 20 mi/h

We know that

1 mi/h= 0.44 m/s

Therefore ,u = 8.94 m/s

Distance ,s= 50 m

Lets take the acceleration of the car = a m/s²

The final speed of the car ,v = 0 m/s

We know that

v²= u² + 2 a s

Now by putting the values

0²= 8.94² + 2 x a x 50

a=-\dfrac{8.94^2}{2\times 50}\ m/s^2

a= - 0.79 m/s²

Therefore the acceleration will be - 0.79 m/s².

6 0
3 years ago
When adjusting the valve clearances on the engine, Technician A says the valves are closed when the valve lifter or follower is
andre [41]

Answer:

A. Technician A only

Explanation:

The camshaft opening ramp is what opens the valve, it starts at the basement of the inner circle and closes at the nose while the camshaft closing ramp allows for closing a valve starts at the nose and closes at the inner base circle. Valve clearance on an engine are performed when closing a valve, and is completed when the valve lifter or follower is on the inner base circle of the camshaft lobe.

7 0
3 years ago
Hey guys.. ans me
Stels [109]

The time taken by the swimmer was 1 hour.

Why?

Since the swimmer is maintaining an angle of 150° while he was swimming, there were two components of the speed (horizontal and vertical). If we want to calculate the time taken by him to cross the river, we need to calculate the vertical speed and consider that the flow's speed is compensated by his horizontal speed.

We can calculate both components of the speed using the following formula:

HorizontalSpeed=Speed*Cos(150\°)\\\\VerticalSpeed=Speed*Sin(150\°)

Now, calculating we have:

HorizontalSpeed=2\frac{Km}{h} *Cos(150\°)=-\sqrt{3} \frac{Km}{h} \\\\VerticalSpeed=2\frac{Km}{h} *Sin(150\°)=1\frac{Km}{h}

Therefore, we have that the horizontal speed is compesating the flow's speed while his vertical speed is used to cross the river which is 1 Km wide.

Hence, we have that the tame taken is:

Time=\frac{RiverWidth}{VerticalSpeed}=\frac{1Km}{1\frac{Km}{h} } =1h

Have a nice day!

7 0
2 years ago
At time=0s, the object is at the 21.0-meter position along the roadway. Where is the object at time = 10 s?
Jet001 [13]
B.) 70m is your answer!
4 0
3 years ago
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