Question

An electron is placed 5.40 cm due north of a charged sphere and experienced a force of 8.30 x 10^-13 N due north. What is the electric field experienced by the electron at that point?

Answer 1

Answer:

The electric field is $E = 5.1*10^6N/C.$

Explanation:

The force $F$ on a charge $q$ in an electric field $E$ is given by

$F = qE$,

which can be rearranged to give

$E = \dfrac{F}{q }$

Now, the force on the electron is $F = 8.30*10^{-13}N$, and its charge is

$q = 1.6*10^{-19}C$; therefore,

$E = \dfrac{8.30*10^{-13}N}{1.6*10^{-19}C}$

$\boxed{E = 5.1*10^6N/C}$