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kaheart [24]
3 years ago
6

How can distillation be used to prepare pure water from tap water?

Chemistry
1 answer:
aleksklad [387]3 years ago
5 0
Distillation can be used to prepare pure water from tap water by first, evaporating the tap water at T = 100 C, by this only the pure water will be evaporated. then condensing the evaporated water by help of an ice bath to collect the pure water that is distilled
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Carbonic acid reacts with water to yield bicarbonate ions and hydronium ions: h2co3+h2o?hco3?+h3o+ identify the conjugate acid-b
Levart [38]
Conjugate base pairs are acid and bases having common features. These features are the equal gain or loss of protons of the pairs. Conjugate pairs should always be one base and one acid. One would not exist without the other. Conjugate acids are the substances that gains protons while conjugates bases are those that loses protons. <span>The substances in the equilibrium reaction that is given is identified as follows: 
HCO3^-      +     H2O <----->   CO3^2-          +             H3O^+ 
 acid                   base         conjugate base           conjugate acid 

HCO3^- ion is an intermediate molecule of CO2 and CO3^2-. When we add OH- to HCO3^-, we produce CO3^2-. And when we add H+ to HCO3, we produce CO2. </span>
7 0
2 years ago
Once again if anyone could help, I would really appreciate your help! Thank you ❤️
Nikolay [14]

Answer:

D

Explanation:

I explained how to do it on your other problem so look there :)

6 0
3 years ago
Which of the following is not found in a nucleotide?
Firlakuza [10]

Amino acid is not found in a nucleotide.

8 0
3 years ago
When the temperature goes up, the volume will also go up
Tju [1.3M]

Answer:

Yes it will

An example is ice, when it melts the volume goes up which means it occupies much more space

4 0
3 years ago
Determine the pH of a KOH solution made by mixing 0.251 g KOH with enough water to make 1.0 × 10 2 mL of solution
vesna_86 [32]

Answer:

pH = 12.65

Explanation:

From the given information:

number of moles =mass in gram / molar mass

number of moles of KOH = mass of KOH / molar mass of KOH

number of moles of KOH =  0.251 g / 56.1 g/mol = 0.004474 mol

For solution :

number of moles = Concentration × volume

concetration = number of moles/ volume

concetration = 0.004474 mol / 0.100 L

concetration  = 0.04474 M

We know that 1 moles KOH result into 1 mole OH⁻ ions

Therefore,  Molarity  of OH⁻ = 0.04474 M

Now,

pOH = -log[OH⁻]

pOH = -log (0.04474) M

pOH = 1.35

Similarly,

pH + pOH = 14

pH = 14 - pOH

pH = 14 - 1.35

pH = 12.65

6 0
2 years ago
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