Answer:
The answer to your question is 2NaCl + 2H₂O ⇒ 2NaOH + Cl₂ + H₂
Explanation:
Original chemical equation
NaCl + H₂O ⇒ NaOH + Cl₂ + H₂
Reactant Element Products
1 Na 1
1 Cl 2
2 H 3
1 O 1
This reactions is unbalanced
2NaCl + 2H₂O ⇒ 2NaOH + Cl₂ + H₂
Reactant Element Products
2 Na 1
2 Cl 2
4 H 4
2 O 2
Now, the reaction is balanced
Given what we know, we can confirm that an example is a situation given that corroborates the information shown, while a non-example is one that does not fall in line with the information provided.
<h3>What are examples of the situations given?</h3>
- A number that is a multiple of 10 is 40, since 10 times 4 equals 40.
- In order to get a product of 10, we can multiply two and five.
- To result in a quotient of 10, we can divide one hundred by ten.
<h3>What are non-examples of the situations given?</h3>
- one non-example of a multiple of 10 would be to multiply three and seven.
- A non-example of a product of 10 is to multiply the number fifty by twenty-five.
- To result in a non-example for a quotient of 10, we can divide the number fifteen by three.
Therefore, given the definition of an example as a situation given that corroborates the information shown, while a non-example is one that does not fall in line with the information provided, we can confirm that the ones listed above are correct.
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It’s chlorine not iodine because as we go down the group non metallic character decreases
The balanced chemical reaction is:
<span>Mg(OH)2 + 2HCl
--> MgCl2 + 2H2O</span>
So we can see that 2 moles of HCl reacts for every 1 mole
of Mg(OH)2.
moles HCl left = 0.125 M * 0.150 L – (0.125 M * 0.040 L) *
2
moles HCl left = 0.00875 mol
So the concentration of H+ ion is:
[H+] = 0.00875 mol / (0.150 L + 0.040 L)
[H+] = 0.046 M
So the pH is:
pH = - log 0.046
<span>pH = 1.34</span>