The solubility equilibrium of PbCl
:

![K_{sp}=[Pb^{2+}][Cl^{-}]^{2}](https://tex.z-dn.net/?f=%20K_%7Bsp%7D%3D%5BPb%5E%7B2%2B%7D%5D%5BCl%5E%7B-%7D%5D%5E%7B2%7D%20%20%20)
![[Cl^{-}] = 2.88 * 10^{-2} M](https://tex.z-dn.net/?f=%20%5BCl%5E%7B-%7D%5D%20%3D%202.88%20%2A%2010%5E%7B-2%7D%20M%20)
![[Pb^{2+}]=\frac{[Cl^{-}]}{2} = \frac{2.88 * 10^{-2}}{2}=1.44 *10^{-2}](https://tex.z-dn.net/?f=%20%5BPb%5E%7B2%2B%7D%5D%3D%5Cfrac%7B%5BCl%5E%7B-%7D%5D%7D%7B2%7D%20%3D%20%5Cfrac%7B2.88%20%2A%2010%5E%7B-2%7D%7D%7B2%7D%3D1.44%20%2A10%5E%7B-2%7D%20%20%20%20)
![K_{sp}=[Pb^{2+}][Cl^{-}]^{2}](https://tex.z-dn.net/?f=%20K_%7Bsp%7D%3D%5BPb%5E%7B2%2B%7D%5D%5BCl%5E%7B-%7D%5D%5E%7B2%7D%20%20%20)
= 
= 
So, the corrected solubility product will be 
In CO2 the dipole moments cancel out, while in H20, they don’t, making it polar. In C02, both oxygens are more electronegative than the carbon, but they pull equally apart from one another, so there is no dipole moment (the pulls cancel)
Answer:
0.89 moles of N2 gas
Explanation:
From Avogadro's law:
V1/n1 = V2/n2
n2 = V2n1/V1
V1=11.2L
V2= 20L
n1=0.5 moles
n2 = ??
Therefore
n2= 20×0.5/11.2= 0.89 moles
the correct answer is combustion
when an organic compounds burns in the presence of oxygen the products are carbon dioxide and water. Combustion reactions yields a large amount of energy
an example for combustion reaction is as follows
combustion of methane;
CH₄ + 2O₂ --> CO₂ + 2H₂O
correct answer is
2. combustion