Answer:
36.2 K
Explanation:
Step 1: Given data
- Initial pressure of the gas (P₁): 8.6 atm
- Initial temperature of the gas (T₁): 38°C
- Final pressure of the gas (P₂): 1.0 atm (standard pressure)
- Final temperature of the gas (T₂): ?
Step 2: Convert T₁ to Kelvin
We will use the following expression.
K = °C +273.15
K = 38 °C +273.15 = 311 K
Step 3: Calculate T₂
We will use Gay Lussac's law.
P₁/T₁ = P₂/T₂
T₂ = P₂ × T₁/P₁
T₂ = 1.0 atm × 311 K/8.6 atm = 36.2 K
Explanation:
Sugar - Pure substance
Magnesium Ribbon - Pure Substance
Vegetable soup Heterogeneous mixture
Bath oil - Homogeneous mixture
Tin of assorted biscuits - Heterogeneous mixture
Peanuts and raisins - Heterogeneous mixture
Copper wire - Pure Substance
Bicarbonate of soda (Baking soda) - Pure Substance
Answer:
technetium, atomic number 43; promethium, number 61; astatine, number 85; francium, number 87; neptunium, number 93; and plutonium, number 94.
Explanation: