Why do you think moles are important for stoichiometry?

an element has a metallic gray appearance. it also has the properties of both a metal and a nonmetal. in which section of the pe

irinina [24]

If it has properties of metal and non metal it is considered a metalloid there are very few spots in which metalloids are located the spots I circled on a blank periodic tables are where the metalloids are located on an actual periodic table your only options are
boron(B) silicon(si) germanium(Ge) arsenic(As)antimony(Sb)tellurium(Te)astatine(At)those are the only places on the periodic table that has metalloids... I hope this helps

6 0

3 years ago

calculate the amount of current that must flow for 50 minutes to a solution of silver trioxonitrate (V) solution to deposit 2 mo

mamaluj [8]

Explanation:

i found this the question is different but I think the situation is same

5 0

2 years ago

Given the following data:

bagirrra123 [75]

$176.0 \; \text{kJ} \cdot \text{mol}^{-1}$

As long as the equation in question can be expressed as the sum of the three equations with known enthalpy change, its $\Delta H$ can be determined with the Hess's Law. The key is to find the appropriate coefficient for each of the given equations.

Let the three equations with $\Delta H$ given be denoted as (1), (2), (3), and the last equation (4). Let $a$ , $b$ , and $c$ be letters such that $a \times (1) + b \times (2) + c \times (3) = (4)$ . This relationship shall hold for all chemicals involved.

There are three unknowns; it would thus take at least three equations to find their values. Species present on both sides of the equation would cancel out. Thus, let coefficients on the reactant side be positive and those on the product side be negative, such that duplicates would cancel out arithmetically. For instance, $3 + (-1) = 2$ shall resemble the number of $\text{H}_2$ left on the product side when the second equation is directly added to the third. Similarly

$\text{NH}_4 \text{Cl} \; (s)$ : $-2 \; a = 1$
$\text{NH}_3\; (g)$ : $-2 \; b = -1$
$\text{HCl} \; (g)$ : $2 \; c = -1$

Thus

$a = -1/2\\b = 1/2\\c = -1/2$ and

$-\frac{1}{2} \times (1) + \frac{1}{2} \times (2) - \frac{1}{2} \times (3)= (4)$

Verify this conclusion against a fourth species involved- $\text{N}_2 \; (g)$ for instance. Nitrogen isn't present in the net equation. The sum of its coefficient shall, therefore, be zero.

$a + b = -1/2 + 1/2 = 0$

Apply the Hess's Law based on the coefficients to find the enthalpy change of the last equation.

$\Delta H _{(4)} = -\frac{1}{2} \; \Delta H _{(1)} + \frac{1}{2} \; \Delta H _{(2)} - \frac{1}{2} \; \Delta H _{(3)}\\\phantom{\Delta H _{(4)}} = -\frac{1}{2} \times (-628.9)+ \frac{1}{2} \times (-92.2) - \frac{1}{2} \times (184.7) \\\phantom{\Delta H _{(4)}} = 176.0 \; \text{kJ} \cdot \text{mol}^{-1}$

3 0

3 years ago

Can a combination reaction be a redox reaction ?

saul85 [17]

Answer:

Yes A redox reaction can be a combination reaction.

Two elements are mixed in a combination reaction to produce a single product.

Explanation:

Example: water formula

2H2 + O2 → 2H2O

Oxygen is reduced in this reaction when electrons are transferred from hydrogen to oxygen and hydrogen is also oxidized since oxygen from hydrogen accepts electrons. Oxygen is the oxidizing agent and hydrogen is the reducing agent.

2H2 + O2 → 2H2O

4 0

3 years ago

What kind of bond will form between the atoms?

Karo-lina-s [1.5K]

ionic bond:

Bond formed when an atom donates its electron and other atom receives those electrons.

polar covalent:

Bond formed by equal sharing of electrons between both the atoms and there is an electronegativity difference between the two atoms.

Nonpolar covalent:

Bond formed by equal sharing of electrons between both the atoms and there is no electronegativity difference between the two atoms.

Metallic:

Formed between two metals.

So the bond between :

Phosphorus and chlorine-polar covalent bond as it is formed by equal sharing of electrons between both the atoms and there is an electronegativity difference between the two atoms.

Potassium and oxygen -ionic bond as here potassium donates its electron and oxygen receives those electrons

Fluorine and fluorine -Non polar covalent bond as formed by equal sharing of electrons between both the atoms and there is no electronegativity difference between the two atoms.

Copper and aluminum-metallic bond as Formed between two metals.

Carbon and fluorine -polar covalent bond as it is formed by equal sharing of electrons between both the atoms and there is an electronegativity difference between the two atoms.

Carbon and hydrogen --Non polar covalent bond as formed by equal sharing of electrons between both the atoms and there is no electronegativity difference between the two atoms.

Aluminum and oxygen--ionic bond as here aluminum donates its electron and oxygen receives those electrons

Silver and copper --metallic bond as Formed between two metals.

6 0

3 years ago