<u>Answer:</u> The volume of the container needed is 554.6 L
<u>Explanation:</u>
To calculate the volume of the gas, we use the equation given by ideal gas which follows:
where,
P = pressure of the gas = 3.0 atm
V = Volume of the gas = ? L
T = Temperature of the gas = ![25^oC=[25+273]K=298K](https://tex.z-dn.net/?f=25%5EoC%3D%5B25%2B273%5DK%3D298K)
R = Gas constant = 
n = number of moles of propane gas = 68.0 moles
Putting values in above equation, we get:
Hence, the volume of the container needed is 554.6 L
Oxygen and glucose that’s all I know
Missing question:
a. C6H12O6
<span>b. CH3OH </span>
<span>c. C12H22O11 </span>
<span>d. NaOH.
</span>Answer is: d. NaOH.
b(solution) = 0,1 m.
ΔT = Kf ·
b(solution) · i.
Kf - the freezing point depression constant.
i - Van 't Hoff factor. Because dissociate on one cation and one anions, sodium hydroxide has i = 2, other molecules has covalent bonds (i = 1, do not dissociate on ions).
Because molality and the freezing point depression constant are constant, greatest freezing point lowering is solution with highest Van 't Hoff factor.
