Answer:
The volume of the balloon will be 5.11L
Explanation:
An excersise to solve with the Ideal Gases Law
First of all, let's convert the pressure in mmHg to atm
1 atm = 760 mmHg
760 mmHg ___ 1 atm
755.4 mmHg ____ (755.4 / 760) = 0.993 atm
922.3 mmHg ____ ( 922.3 / 760) = 1.214 atm
T° in K = 273 + °C
28.5 °C +273 = 301.5K
26.35°C + 273= 299.35K
P . V = n . R .T
First situation: 0.993atm . 6.25L = n . 0.082 . 301.5K
(0.993atm . 6.25L) / 0.082 . 301.5 = n
0.251 moles = n
Second situation:
1.214 atm . V = 0.251 moles . 0.082 . 301.5K
V = (0.251 moles . 0.082 . 301.5K) / 1.214 atm
V = 5.11L
Answer:For Fe
Z=26
Explanation:
1s2 2s2 2p6 3s2 3p6 4s2 3d6
Are there 26 electrons here? Why should there be 26?
So going back to the inert gas, argon ( Z=18 ), we get
[Ar] 4s2 3d6
Make sure to check your work by counting the electrons you have
Answer: Green is 550 nm and blue is 470 nm
Answer:
6.25 X10^{-9} = Ka
Explanation:
The ionic equation for the hydrolysis of the cation of the given salt will be:
The expression for Ka will be:
Ka = ![\frac{[H^{+}][MOH]}{[M^{+}]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BH%5E%7B%2B%7D%5D%5BMOH%5D%7D%7B%5BM%5E%7B%2B%7D%5D%7D)
As given that the concentration of the salt is 0.1 M and pH of solution = 4.7, we can determine the concentration of Hydrogen ions from the pH
pH = -log [H⁺]
[H⁺] = antilog(-pH) = antilog (-4.7) = 2 X 10⁻⁵ M = [MOH]
Let us calculate Ka from this,
Ka = 
The relation between Ka an Kb is
KaXKb =10⁻¹⁴
