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Butoxors [25]
3 years ago
13

A solution is prepared by diluting 50.00 ml of 2.575 m solution of hno3 to 250.0 ml. what is the molarity of the resulting solut

ion?
Chemistry
2 answers:
larisa [96]3 years ago
8 0
Thank you for posting your question here at brainly. Below are the choices that can be found elsewhere:

12.88 M 
<span>0.1278 M </span>
<span>0.2000 M </span>
<span>0.5150 M
</span>
Below is the answer:

<span>5 times diluted (250/50),so 2.575/5=0.515 M
</span>
I hope it helps. 
Lilit [14]3 years ago
8 0

Answer:

M_2=0.515M

Explanation:

Hello,

In this case, since the dilution process does not affect the quantity of moles in the solution (from state 1 to 2), one leverages the aforesaid conservation and subsequently uses the definition of molarity to obtain the dilution formula as shown below:

n_1=n_2\\M=\frac{n}{V} \\M_1V_1=M_2V_2

Next, solving for the molarity after the dilution, M_2, one obtains:

M_2=\frac{M_1V_1}{V_2}=\frac{2.575M*50.00mL}{250.0mL}\\M_2=0.515M

Best regards.

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What is Q= mc delta t
Mariulka [41]

Answer:

Explanation:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

The substances with higher value of specific heat capacity require more heat to raise the temperature by one degree as compared the substances having low value of specific heat capacity.For example,

The specific heat capacity of oil is 1.57 j/g. K and for water is 4.18 j/g.K. So, water take a time to increase its temperature by one degree by absorbing more heat while oil will heat up faster by absorbing less amount of heat.

Consider that both oil and water have same mass of 5g and change in temperature is 15 K. Thus amount of heat thy absorbed to raise the temperature is,

For oil:

Q = m.c. ΔT

Q = 5 g× 1.67 j/g K × 15 K

Q = 125.25 j

For water:

Q = m.c. ΔT

Q = 5 g× 4.18 j/g K × 15 K

Q = 313.5 j

we can observe that water require more heat which is 313.5 j to increase its temperature.

6 0
3 years ago
What element is in group 17 and period 2 of the periodic table?
Natali [406]

Answer:

Group 17 elements:

Flourine (F), Chlorine (Cl), Bromine (Br), Iodine (I), and Astatine (As).

Period 2 elements:

Lithium (Li), Beryllium (Be), Boron (B), carbon (C), Nitrogen (N), Oxygen (O), flourine (F), And Neon.

3 0
3 years ago
A solution is 40.00% by volume benzene (C6H6) in carbon tetrachloride at 20°C. The vapor pressure of pure benzene at this temper
finlep [7]

Answer:

The total vapor pressure is 84.29 mmHg

Explanation:

Step 1:  Data given

Solution = 40.00 (v/v) % benzene in CCl4

Temperature = 20.00 °C

The vapor pressure of pure benzene at 20.00 °C = 74.61 mmHg

Density of benzene is 0.87865 g/cm3

The vapor pressure of pure carbon tetrachloride is 91.32 mmHg

We suppose the total volume = 100 mL

Step 2: Calculate volume benzene and CCl4

40 % benzene = 40 mL

60 % mL CCl4 = 60 mL

Step 3: Calculate mass benzene

Mass = density * volume

Mass of benzene = 40.00 mL *  0.87865 g/mL = 35.146 g

Step 4: Calculate moles of benzene

Moles = mass / molar mass

Number of moles of benzene  = 35.146 grams / 78 g/mol  = 0.45059 mol

Step 5: Calculate mass of CCl4

Mass of CCl4 = 60 mL * 1.5940 g/mL = 95.64 g

Step 6: Calculate moles CCl4

Number of moles of CCl4 = 95.64 grams / 154g/mol = 0.62104 mol

Step 7: Calculate total number of moles

Total number of moles = moles benzene + moles CCl4

0.45059 moles + 0.62104 moles = 1.07163 mol

Step 8: Calculate mole fraction benzene and CCl4

Mole fraction = moles benzene / total moles

Mole fraction of benzene = 0.45059 / 1.07163 = 0.4205

Mole fraction of CCl4 = 0.62104 / 1.07163 = 0.5795

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Partial pressure of benzene = 0.4205 * 74.61 = 31.37 mmHg

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Total vapor pressure = 31.37 + 52.92 = 84.29 mmHg

The total vapor pressure is 84.29 mmHg

7 0
3 years ago
Now they feel it is best to have you identify an unknown gas based on its properties. Suppose 0.508 g of a gas occupies a volume
pishuonlain [190]

Answer: Option (b) is the correct answer.

Explanation:

The given data is as follows.

             mass = 0.508 g,               Volume = 0.175 L

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As per the ideal gas law, PV = nRT.

where,  n = no. of moles = \frac{mass}{\text{molar mass}}

Hence, putting all the given values into the ideal gas equation as follows.

               PV = \frac{mass}{\text{molar mass}} \times RT            

           1 atm \times 0.175 L = \frac{0.508 g}{\text{molar mass}} \times 0.0821 L atm/ K mol \times 298 K  

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As the molar mass of a chlorine atom is 35.4 g/mol and it exists as a gas. So, molar mass of Cl_{2} is 70.8 g/mol or 71 g/mol (approx).

Thus, we can conclude that the gas is most likely chlorine.

4 0
3 years ago
True of false. A d-orbital lies in the x, y, and z area defined by the geometric axis of space.​
evablogger [386]

Answer:

true

Explanation:

3 0
2 years ago
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