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Butoxors [25]
3 years ago
13

A solution is prepared by diluting 50.00 ml of 2.575 m solution of hno3 to 250.0 ml. what is the molarity of the resulting solut

ion?
Chemistry
2 answers:
larisa [96]3 years ago
8 0
Thank you for posting your question here at brainly. Below are the choices that can be found elsewhere:

12.88 M 
<span>0.1278 M </span>
<span>0.2000 M </span>
<span>0.5150 M
</span>
Below is the answer:

<span>5 times diluted (250/50),so 2.575/5=0.515 M
</span>
I hope it helps. 
Lilit [14]3 years ago
8 0

Answer:

M_2=0.515M

Explanation:

Hello,

In this case, since the dilution process does not affect the quantity of moles in the solution (from state 1 to 2), one leverages the aforesaid conservation and subsequently uses the definition of molarity to obtain the dilution formula as shown below:

n_1=n_2\\M=\frac{n}{V} \\M_1V_1=M_2V_2

Next, solving for the molarity after the dilution, M_2, one obtains:

M_2=\frac{M_1V_1}{V_2}=\frac{2.575M*50.00mL}{250.0mL}\\M_2=0.515M

Best regards.

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\\ \sf\longmapsto CaCO_3

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