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DiKsa [7]
3 years ago
5

Two systems are in oscillation: a simple pendulum swinging back and forth through a very small angle and a block oscillating on

a spring. The block-spring system takes twice as much time as the pendulum to complete one oscillation. What could be done to make the two systems oscillate with the same period
Physics
1 answer:
aleksley [76]3 years ago
3 0

Answer:

Here to make the two systems oscillate with same period either decrease the mass of the block system to one fourth or increase the length of the string to four times

Explanation:

we know that time period of block spring system is  2\pi\sqrt{\frac{m}{k} }

   where m = mass of the block

              k= spring constant

      and also time period of simple pendulum making small oscillations  is 2\pi\sqrt{\frac{l}{g} }

      where l = length of the pendulum    

                 g = acceleration due to gravity

   so here to make time period of the both systems to be same either we can decrease the block system time period to its half or double the time period of the pendulum.

 To decrease the time period of block spring system to half its value from above equation we need to decrease the mass of the block to one fourth

 and to increase the time period of the pendulum we need to increase length by four times .

   

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Each ball has a negligible size and a mass of 11.5 kg and is attached to the end of a rod whose mass may be neglected. The rod i
Digiron [165]

Answer:

3.31m/s

Explanation:

Angular momentum for 3s is

L = L_i_n_i + L_3_s

L = 2(11.5kg) + \int\limits^ {3s}_ {0s} {(t^2 + 2)} \, dt

L = 23kg+(\frac{t^3}{3} +2t)^ {3s}_ {0s}\\\\L=38kgm/s

Moment if inertia is

I = 2ml^2

I = 2(11.5)(0.5)^2\\\\I=5.75kgm^2

Angular speed

ω = L/I

= 38 / 5.75\\\\=6.61

The speed of each ball is

V = ωL

= 6.61\times0.5\\\\= 3.31m/s

7 0
3 years ago
What are the products of a fusion reaction? Check all that apply. Lighter atoms energy heavier atoms a neutron a proton.
svet-max [94.6K]

The process by which two or more tiny nuclei unite to generate a bigger nucleus is known as a nuclear fusion reaction. Heavier atoms are products of a fusion reaction.

<h3 /><h3>What is nuclear fusion?</h3>

The process by which two or more tiny nuclei unite to generate a bigger nucleus is known as a nuclear fusion reaction.

For example, the fusion of two hydrogen atoms produces more energy than the fusion of one helium atom, and surplus energy is expelled into space upon binding.

Hence heavier atoms are e products of a fusion reaction.

To learn more about nuclear fusion refer to the link;

brainly.com/question/14019172

6 0
2 years ago
Which statement is correct? When a positively charged atom looses an electron to a positively charged atom, two neutral atoms ar
vazorg [7]
I believe the answer is "When a neutral atom looses an electron to another neutral atom, two charged atoms are created."
3 0
3 years ago
Read 2 more answers
On another planet gravity has a value of 5.5 m/s . If an object is dropped how long will it take to fall 53 m?
Nikolay [14]

Answer:

4.4 seconds

Explanation:

Given:

a = -5.5 m/s²

v₀ = 0 m/s

y₀ = 53 m

y = 0 m

Find: t

y = y₀ + v₀ t + ½ at²

0 = 53 + 0 + ½ (-5.5) t²

0 = 53 − 2.75 t²

t = 4.39

Rounded to two significant figures, it takes 4.4 seconds for the object to land.

7 0
3 years ago
Suppose a wheel with a tire mounted on it is rotating at the constant rate of 2.83 times a second. A tack is stuck in the tire a
timama [110]

Answer:

The tangential speed of the tack is 6.988 meters per second.

Explanation:

The tangential speed experimented by the tack (v), measured in meters per second, is equal to the product of the angular speed of the wheel (\omega), measured in radians per second, and the distance of the tack respect to the rotation axis (R), measured in meters, length that coincides with the radius of the tire. First, we convert the angular speed of the wheel from revolutions per second to radians per second:

\omega = 2.83\,\frac{rev}{s} \times \frac{2\pi\,rad}{1\,rev}

\omega \approx 17.781\,\frac{rad}{s}

Then, the tangential speed of the tack is: (\omega \approx 17.781\,\frac{rad}{s}, R = 0.393\,m)

v = \left(17.781\,\frac{rad}{s} \right)\cdot (0.393\,m)

v = 6.988\,\frac{m}{s}

The tangential speed of the tack is 6.988 meters per second.

7 0
3 years ago
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