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DiKsa [7]
3 years ago
5

Two systems are in oscillation: a simple pendulum swinging back and forth through a very small angle and a block oscillating on

a spring. The block-spring system takes twice as much time as the pendulum to complete one oscillation. What could be done to make the two systems oscillate with the same period
Physics
1 answer:
aleksley [76]3 years ago
3 0

Answer:

Here to make the two systems oscillate with same period either decrease the mass of the block system to one fourth or increase the length of the string to four times

Explanation:

we know that time period of block spring system is  2\pi\sqrt{\frac{m}{k} }

   where m = mass of the block

              k= spring constant

      and also time period of simple pendulum making small oscillations  is 2\pi\sqrt{\frac{l}{g} }

      where l = length of the pendulum    

                 g = acceleration due to gravity

   so here to make time period of the both systems to be same either we can decrease the block system time period to its half or double the time period of the pendulum.

 To decrease the time period of block spring system to half its value from above equation we need to decrease the mass of the block to one fourth

 and to increase the time period of the pendulum we need to increase length by four times .

   

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Snezhnost [94]

Answer:

C. The number of protons.

Explanation:

All atoms of mercury will remain the same while different isotopes may have different number of neutrons.

For example, mercury has 80 protons, correlating with its atomic number. However, the number of protons, neutrons, and electrons could vary between each atom. If there are 80 protons, then there has to be 80 electrons. This means that the protons have to be the same in order to apply to all atoms of mercury

8 0
4 years ago
You can jump 3 m (10 feet) off of a diving board and into a swimming pool and be uninjured. However, if you jumped from the same
Mrac [35]

Answer:

1) this is due to force due to momentum change of a body falling from such a height.

2) they move with velocity of 2.69 m/s towards the right.

Explanation:

1) in the case where one jumps 3 meters into water, the water deform on impact extending the time of impact for your body's momentum to get to zero, so that the time it takes for the momentum of your body due to your mass and your velocity to get to zero is relatively long lessening the force felt due to the impact.

For a fall from the same height onto a concrete, the concrete does not deform at all. This means that there is a very short time for your momentum to get to zero and hence the force is huge. In order to cushion this a little, your body deforms in a bid to reduce the force and this is very deadly.

This is in line with Newton's second law of motion which states that the rate of change of momentum is proportional to the force produced.

2)

M1 = 125 kg

M2 = 80 kg

V1 = 2.5 m/s

V2 = 3 m/s

From momentum conservation, total initial momentum must be equal to the total momentum after collision.

Momentum = mass x velocity.

That is,

M1V1 + M2V2 = (M1 + M2) Vf

Where Vf is their final velocity together.

Note that the masses stick together because the collision is inelastic.

Substituting and solving, we have

(125 x 2.5) + (80 x 3) = (125 + 80)Vf

312.5 + 240 = 205Vf

552.5 = 205Vf

Vf = 552.5/205 = 2.69 m/s

Note that the linebacker runner has the greater momentum 125 x 2.5 = 312.15

This means they both move to the right at velocity of 2.69 m/s

7 0
3 years ago
Ang larong Latin at Sisiw ay________________________.
brilliants [131]

larong pinoy

Explanation:

ito ay larong Pinoy

3 0
3 years ago
When a car's starter is in use, it draws a large current. The car's lights draw much less current. As a certain car is starting,
ad-work [718]

Answer:

EMF = 11.35 V

R = 0.031Ω

Explanation:

To find the battery's EMF and the internal resistance we need to use Ohm's law:

V = IR

Where:

V: is the voltage

I: is the current

R is the resistance

We have:

The current through the battery is 64.2 A and the potential difference across the battery terminals is 9.36 V:

\epsilon = V + IR      

\epsilon = 9.36 V + 64.2A*R   (1)

When only the car's lights are used, the current through the battery is 1.96 A and the terminal potential difference is 11.3 V:

\epsilon = 11.3 V + 1.96A*R   (2)

By solving equation (1) and (2) for R we have:

9.36 V + 64.2A*R = 11.3 V + 1.96A*R

R = \frac{1.94 V}{62.24A} = 0.031 \Omega

Hence, the internal resistance is 0.031 Ω.

Now, by entering R into equation (1) we can find the battery's EMF:

\epsilon = 9.36 V + 64.2A*0.031 \Omega

\epsilon = 11.35 V

Therefore, the battery's EMF is 11.35 V.

I hope it helps you!                

8 0
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Chemical equation is a symbolic representation of a chemical reaction which is written in the form of symbols and chemical formulas.The reactants are present on the left hand side while the products are present on the right hand side.

A plus sign is present between reactants and products if they are more than one in any case and an arrow is present pointing towards the product side which indicates the direction of the reaction .There are coefficients present next to the chemical symbols and formulas .

The first chemical equation was put forth by Jean Beguin in 1615.By making use of chemical equations the direction of reaction ,state of reactants and products can be stated. In the chemical equations even the temperature to be maintained and catalyst can be mentioned.

Learn  more about chemical equation,here:

brainly.com/question/28294176

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