Answer:
The final velocity of puck 2 is 6 m/s to the right
Explanation:
Given;
mass of puck 1, m₁ = 0.5 kg
mass of puck 2, m₂ = 2 kg
initial velocity of puck 1, u₁ = 20 m/s
initial velocity of puck 1, u₂ = 0
final velocity of puck 1, v₁ = -4 m/s
Let the final velocity of puck 2 = v₂
Applying the principle of conservation linear momentum, total momentum before collision is equal to total momentum after collision.
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
(0.5 x 20) + (2 x 0) = (0.5 x -4) + 2v₂
10 = -2 + 2v₂
2v₂ = 12
v₂ = 12/2
v₂ = 6 m/s
This positive final velocity of puck 2, indicates that it moved to the right.
