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3 years ago

A total solar eclipse is visible from

Physics

2 answers:

leonid [27]3 years ago

6 0

Answer:

b. only within the moon’s umbra.

Explanation:

A total solar eclipse occurs when the moon blocks the sunlight falling on the Earth. It occurs at the bright side of the Earth when Earth passes through the umbra of the moon.

When sun, moon and Earth align in a straight line, the disk of the moon is able to block the disk of the sun causing the sunlight to get blocked. Shadow of moon falls on the Earth. A total eclipse occurs when the sun is complete blocked and there is total darkness. It is visible from those areas which pass through the moon's umbra.

True [87]3 years ago

5 0

Hey! Hope that this helps. I'm fairly certain the answer is B, because I know that it's not visible from all over the earth, so that eliminates A, but doing some research I found out that an observer in the umbra experiences a total eclipse.

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A private aviation helicopter's main rotor blades rotate at approximately

Arisa [49]

Answer: 7.5 rev/s

Explanation:

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However, we are asked to express this $\omega$ in the International Systrm (SI) units. In this sense, the SI unit for time is second ( $s$ ):

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3 years ago

A transformer consisting of two coils wrapped around an iron core is connected to a generator and a resistor (Resistor is connec

V125BC [204]

Answer:

The peak emf of the generator is 40.94 V.

Explanation:

Given that,

Number of turns in primary coil= 11

Number of turns in secondary coil= 18

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Using relation of number of turns and emf

$\dfrac{N_{1}}{N_{2}}=\dfrac{E_{1}}{E_{2}}$

$E_{1}=\dfrac{N_{1}}{N_{2}}\times E_{2}$

Where, N₁ = Number of turns in primary coil

N₂ = Number of turns in secondary coil

E₂ = emf across secondary coil

Put the value into the formula

$E_{1}=\dfrac{11}{18}\times67$

$E_{1}=40.94\ V$

Hence, The peak emf of the generator is 40.94 V.

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2 years ago

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VikaD [51]

Answer: it should be c and d

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