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ycow [4]
3 years ago
10

A total solar eclipse is visible from

Physics
2 answers:
leonid [27]3 years ago
6 0

Answer:

b. only within the moon’s umbra.    

Explanation:

A total solar eclipse occurs when the moon blocks the sunlight falling on the Earth. It occurs at the bright side of the Earth when Earth passes through the umbra of the moon.

When sun, moon and Earth align in a straight line, the disk of the moon is able to block the disk of the sun causing the sunlight to get blocked. Shadow of moon falls on the Earth. A total eclipse occurs when the sun is complete blocked and there is total darkness. It is visible from those areas which pass through the moon's umbra.

True [87]3 years ago
5 0
Hey! Hope that this helps. I'm fairly certain the answer is B, because I know that it's not visible from all over the earth, so that eliminates A, but doing some research I found out that an observer in the umbra experiences a total eclipse.
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Dos cargas Q1=2pc y Q2=4pc estan separadas por una distancia de 6cm ¿con que fuerza se atraen?
noname [10]

Here we can use coulomb's law to find the force between two charges

As per coulombs law

]tex]F = \frac{kq_1q_2}{r^2}[/tex]

here we have

k = 9 * 10^9

q_1 = 2pC

q_2 = 4pC

r = 6cm = 0.06 m

now by using the above equation we have

F = \frac{9*10^9 * 2*10^{-12} * 4*10^{-12}}{0.06^2}

F = 2 * 10^{-11} N

so here the force between two charges is of above magnitude and this will be repulsive force between them as both charges are of same sign.

3 0
3 years ago
What is the build up of electrons on a surface
Minchanka [31]

Answer:

Static energy

Explanation:

Think of it as a balloon rubbing against your hair, the two attractions of friction causes Static energy.

5 0
3 years ago
On a hot summer day in the state of Washington while kayaking, I saw several swimmers jump from a railroad bridge into the Snoho
Svetlanka [38]

Answer: part a: 19.62m

part b: 19.62 m/s

part a: 2.83 secs

Explanation:If the air resistance is ignored then the swimmer experience free fall under gravity hence

u=0

a=9.81 m/s2

t=2 secs

s=ut+0.5at^2

s=h

h=0*2+0.5*9.81*2^2\\h=19.62 meters

Part b

v=u+at\\v=0+9.81*2\\v=19.62m/s

Part c

now we have h=2*19.62=39.24

39.24=0+0.5*9.81*t^2\\t^2=8\\t=2.83 secs

4 0
3 years ago
A copper wire 20 m long and 4mm in diameter is attached to the Ceiling and a 400 N
Fiesta28 [93]

Answer:

A

Explanation:

5 0
2 years ago
What are two examples of common units for each of the above measurements
kap26 [50]

Density: g/mL, kg/cubic meter  

Volume: L, teaspoon  

Mass: g, MeV/sq. C

3 0
3 years ago
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