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lora16 [44]
3 years ago
12

Calculate the enthalpy of the formation of butane, C4H10, using the balanced chemical equation and the standard value below:

Chemistry
1 answer:
zavuch27 [327]3 years ago
6 0

Answer:

+125.4 KJmol-1

Explanation:

∆H C4H10(g) = -2877.6kJ/mol

∆H C(s)=-393.5kJ/mol

∆H H2(g) = -285.8

∆H reaction= ∆Hproducts - ∆H reactants

∆H reaction= (-2877.6kJ/mol) - [4(-393.5kJ/mol) +5(-285.8)]

∆H reaction= +125.4 KJmol-1

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A city in Laguna generates 0.96 kg per capita per day of Municipal Solid Waste (MSW). Makati City in Metro Manila generates 1.9
mamaluj [8]

Answer:

i) amount of MSW generated:

Laguna: 19200 Kg/day

Makati: 38000 Kg/day

ii) number of trucks to collect twice weekly:

Laguna: 3 trucks

Makati: 5 trucks

iii) volume of MSW in tons that enter landfill/week:

Laguna: 147.84 ton/week

Makati: 292 ton/week

Explanation:

i) Laguna: 0.96 Kg person / day of MSW * 20000 = 19200 Kg MSW / day

⇒ Laguna: 19200 Kg/day * ( 7day/ week ) = 134400 Kg/week

Makati: 1.9 Kg person / day of MSW * 20000 = 38000 Kg MSW / day

⇒ Makati: 38000 Kg/day * ( 7day/week ) = 266000 Kg/week

ii)  truck capacity = 4.4 ton * ( Kg / 0.0011 ton ) = 4000 Kg

⇒ quote/day = 4000 Kg * 0.75 = 3000 Kg

⇒ loads/day = 2 * 3000 kg = 6000 Kg

⇒ operate/week = 5 * 6000 Kg = 30000 Kg

∴ Laguna:  number of trucks needed/week= 134400 / 30000  = 4.48 ≅ 5 trucks

⇒ number of trucks to collect twice weekly = 5 / 2 = 2.5 ≅ 3 trucks

∴ Makati : number of trucks needed/week = 266000 / 30000 = 8.86 ≅ 9 trucks

⇒ number of trucks to collect twice weekly = 9 / 2 = 4.5 ≅ 5 trucks  

iii) enter landfill/week:

Laguna: 134400Kg MSW/week * ( 0.0011 ton/Kg ) = 147.84 ton/week

Makati: 266000Kg MSW/week * ( 0.0011 ton/Kg ) = 292 ton/week

4 0
3 years ago
An aqueous sodium acetate, NaC2H3O2 , solution is made by dissolving 0.395 mol NaC2H3O2 in 0.505 kg of water. Calculate the mola
liq [111]

<u>Answer:</u> The molality of NaC_2H_3O_2 solution is 0.782 m

<u>Explanation:</u>

Molality is defined as the amount of solute expressed in the number of moles present per kilogram of solvent. The units of molarity are mol/kg. The formula used to calculate molality:

\text{Molality of solution}=\frac{\text{Moles of solute}}{\text{Mass of solvent (in kg)}} .....(1)

Given values:

Moles of NaC_2H_3O_2 = 0.395 mol

Mass of solvent (water) = 0.505 kg

Putting values in equation 1, we get:

\text{Molality of }NaC_2H_3O_2=\frac{0.395mol}{0.505kg}\\\\\text{Molality of }NaC_2H_3O_2=0.782m

Hence, the molality of NaC_2H_3O_2 solution is 0.782 m

8 0
3 years ago
A gas fills a balloon at a temperature of 27 C and 101.325 kPa of pressure. What will the pressure of the balloon be if the gas
JulijaS [17]

135.1‬kPa

Explanation:

Given parameters:

T1 = 27°C

P1  = 101.325 kPa

T2 = 127°C

Unknown:

P2 = ?

Solution:

Using a derivative of the combined gas law where we assume that the gas has a constant volume, we can solve for the unknown.

 At constant volume:

           \frac{P1}{T1}  = \frac{P2}{T2}

P1 is the initial pressure

T1 is the initial temperature

P2 is the final pressure

T2 is the final temperature

  Take the given temperature to K

T1 = 27 + 273 = 300K

T2 = 127 + 273  = 400K

 Input the variables:

    \frac{101.325}{300}  = \frac{P2}{400}

  P2 = 135.1‬kPa

learn more:

Boyle's law brainly.com/question/8928288

#learnwithBrainly

3 0
3 years ago
Which particle makes the atom an unstable isotope?
Galina-37 [17]
Instability of an atoms nucleus can result from an excess of either neutrons or protons . So neutrons and protons .
6 0
3 years ago
Solve the following equation (y = 1.2345x – 0.6789) for x, given that y = 0.570
Andrews [41]

x = 1.01

Explanation:

Given equation:

   y = 1.2345x – 0.6789

   y = 0.570

Problem:

Solving for x

The variables in this equation are y and x

They can take up any value since they are variables.

  Since we have been given y = 0.570

        y = 1.2345x – 0.6789

To solve for x, we simply substitute for y in the equation;

     since  y = 0.570

     0.57 = 1.2345x – 0.6789

    add 0.6789 to both sides;

 0.57 + 0.6789 =  1.2345x – 0.6789 + 0.6789

  1.2489‬ =   1.2345x

Divide both sides by  1.2345

 \frac{1.2489}{  1.2345} = \frac{  1.2345x }{ 1.2345}

    x = 1.01

learn more:

Equations brainly.com/question/9045597

#learnwithBrainly

 

7 0
3 years ago
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