If you see ##### in a cell, you should
1 answer:
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Solution :
The motion in the y direction.
The time taken by the toy rocket to hit the ground,
S = distance travelled = 30 m
u = 0 m/s
a =
t= time in seconds
Therefore,
t = 2.47 sec
Now motion in the x direction,
u = 12 m/sec
Upon integration 'v' with respect to 't'
Once again integrating with respect to t,
= 0.0176+29.64
= 29.65 m
Therefore, the toy rocket will hit the ground at 29.65 m from the building.
Answer:
The acceleration of the electron is 1.457 x 10¹⁵ m/s².
Explanation:
Given;
initial velocity of the emitted electron, u = 1.5 x 10⁵ m/s
distance traveled by the electron, d = 0.01 m
final velocity of the electron, v = 5.4 x 10⁶ m/s
The acceleration of the electron is calculated as;
v² = u² + 2ad
(5.4 x 10⁶)² = (1.5 x 10⁵)² + (2 x 0.01)a
(2 x 0.01)a = (5.4 x 10⁶)² - (1.5 x 10⁵)²
(2 x 0.01)a = 2.91375 x 10¹³
Therefore, the acceleration of the electron is 1.457 x 10¹⁵ m/s².