A pallet of bricks is to be suspended by attaching a rope to it and connecting the other end to a couple of heavy crates on the
roof of a building, as shown. The rope pulls horizontally on the lower crate, and the coefficient of static friction between the lower crate and the roof is 0.666. What is the weight of the heaviest pallet of bricks that can be supported this way?
A. 400 lb
B. 350 lb
C. 250 lb
D. 266 lb
A. 400 lb
B. 350 lb
C. 250 lb
D. 266 lb
1 answer:
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Answer:
W = 0.678 rad/s
Explanation:
Using the conservation of energy:
Roll up and hill without slipping is the sumatory of two energys, rotational and translational, so:
where I is the moment of inertia, W the angular velocity at the base of the hill, m the mass of the ball, V the velocity at the base of the hill, g the gravity and h the altitude.
First, we will find the moment of inertia as:
I =
where m is the mass and R the radius, so:
I =
I = 36.26 Kg*m^2
Then, replacing values on the initial equation, we get:
also we know that:
V =WR
so:
Finally, solving for W, we get:
W = 0.678 rad/s