The efficiency<span> of a heat engine can be calculated as the ratio of the work obtained to the heat energy put in at the high temperature,
efficiency = Work_max/T</span>high<span>.
or
efficiency=TH-TL/TH,
where TH is the high temperature and TL is the low temperature.</span><span>
In our case the heat engine operates between 600K and 800K. SO, TH=800K and TL=600K.
The efficiency is: e=800-600/800=200/800=0,25</span>
Answer:
The force on the charge at the origin is 0 N .
Explanation:
All charges are positive. So, in x axis force exerted by the charge located in the position (10 cm, 0 cm) will be canceled with the force exerted by the charge located in the position (-10 cm, 0 cm). In the same way, in y axis the force exerted by the charge located in the position (0 cm, 10 cm) will be canceled with the force exerted by the charge located in the position (0 cm, -10 cm).
Answer:
20 = 30 / t1
t1 = 3/2
40 = 30 / t2
t2 = 3/4
average speed = total distance / total time taken
= 30 + 30 / 3/2 + 3/4
= 60 /9/4
= 60 × 4/9
= 26.667
The rock's height <em>y</em> at time <em>t</em> is given by
<em>y</em> = 45 m + (7.2 m/s) <em>t</em> - 1/2 <em>g</em> <em>t </em>²
where <em>g</em> = 9.80 m/s² is the magnitude of the acceleration due to gravity. Set <em>y</em> = 0 and solve for <em>t</em> :
0 = 45 m + (7.2 m/s) <em>t</em> - 1/2 <em>g</em> <em>t </em>² → <em>t</em> ≈ 3.9 s