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gayaneshka [121]
3 years ago
9

Convert 3.00 moles As2S3 to grams.

Chemistry
2 answers:
givi [52]3 years ago
7 0

738.1146 grams, your're welcome

Setler [38]3 years ago
4 0

Answer:

738 grams

Explanation:

As2S3 is called Arsenic Sulfide.

The formula needed here is

Number of moles (n) = m ÷ mm

where m = mass of the substance/compound

        mm = molar mass of the same substance/compound

Here, the number of moles has been given to be 3 moles, we can determine the molar mass of the substance from the chemical formula given, hence our unknown is the mass of the compound .

Molar mass of Arsenic (As) is 75 g/mol while that of Sulfur is 32 g/mol.

Hence, the molar mass of the compound; As2S3 will be

(75 x 2) + (32 x 3) = 246 g/mol

From the formula given earlier, we can deduce that mass of As2S3 will be number of moles multiplied by molar mass of As2S3

m = n x mm

m = 3 x 246

m = 738 grams

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Suppose that 0.1000 mole each of H2and I2are placed in a 1.000-L flask, stoppered, and the mixture is heated to 425oC. At equili
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<u>Answer:</u> The value of equilibrium constant for the given reaction is 56.61

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We are given:

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\text{Molarity of solution}=\frac{\text{Number of moles}}{\text{Volume}}

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Equilibrium concentration of iodine gas = 0.0210 M

The chemical equation for the reaction of iodine gas and hydrogen gas follows:

                         H_2+I_2\rightleftharpoons 2HI

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<u>At eqllm:</u>          0.1-x   0.1-x   2x

Evaluating the value of 'x'

\Rightarrow (0.1-x)=0.0210\\\\\Rightarrow x=0.079M

The expression of K_c for above equation follows:

K_c=\frac{[HI]^2}{[H_2][I_2]}

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[H_2]_{eq}=(0.1-x)=(0.1-0.079)=0.0210M

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K_c=\frac{(0.158)^2}{0.0210\times 0.0210}\\\\K_c=56.61

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<u>Answer:</u>

<u>For a:</u> The isotopic representation of iodine is _{53}^{131}\textrm{I}

<u>For b:</u> The isotopic representation of cesium is _{55}^{137}\textrm{Cs}

<u>For c:</u> The isotopic representation of strontium is _{38}^{52}\textrm{Sr}

<u>Explanation:</u>

The isotopic representation of an atom is: _Z^A\textrm{X}

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Z = Atomic number of the atom

A = Mass number of the atom

X = Symbol of the atom

  • <u>For a:</u>

We are given:

Number of neutrons = 78

Atomic number of iodine = 53 = Number of protons

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Thus, the isotopic representation of iodine is _{53}^{131}\textrm{I}

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We are given:

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Number of neutrons = 52

Atomic number of strontium = 38 = Number of protons

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