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Mariana [72]
3 years ago
5

Reflection occurs when a wave _____.

Physics
2 answers:
madam [21]3 years ago
8 0

Answer: The correct answer is " bounces off an object".

Explanation:

Reflection occurs when a wave bounces off an object.  

For example, when a ray of light incidents on the surface of a plane mirror. The light gets reflected from the plane mirror because of the silver polishing on the backside of the mirror.

There are two laws of reflection:

(1) The reflected ray, the incident ray and the normal to the surface of the mirror are all lie in the same plane.

(2) The angle of reflection is equal to the angle of incidence.

faust18 [17]3 years ago
3 0
When they bounce off a barrier
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What is the frequency of a microwave with a wavelength of 3.52 mm?
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As per the question the wavelength of the microwave is given as 3.52 mm.

we are asked to calculate the frequency of the wave.

we know that microwave is a electromagnetic wave.

As per Clark Maxwell's electromagnetic theory ,every electromagnetic wave moves with a velocity equal to the velocity of light in vacuum and that is equal to 3×10^8 m/s.

From the equation of the wave,we know that velocity of wave is the product of frequency and wavelength.

Mathematically   wave velocity v=f*\lambda   where f is the frequency of the wave and \lambda is the wavelength.

As per the question \lambda=3.52 mm

                                               = 3.52*10^{-3} m

                       Here  v=c=3*10^{8} m/s

Hence frequency of the wave f=\frac{v}{\lambda}

                                                       =\frac{3*10^{8} }{3.52*10^{-3} } s^{-1}

                                                        =0.852272727272*10^{11} Hz

Here Hertz [Hz] is the unit of frequency.                      

                                             



6 0
3 years ago
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A skater is spinning at 15.0 rad/s with a rotational inertia of 8.0 kg m? If she changes her rotational inertia to 5.0 kg mº, wh
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Answer:Idrk man

Explanation:

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3 years ago
An electron in a mercury atom drops
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Since the electron dropped from an energy level i to the ground state by emitting a single photon, this photon has an energy of 1.41 × 10⁻¹⁸ Joules.

<h3>How to calculate the photon energy?</h3>

In order to determine the photon energy of an electron, you should apply Planck-Einstein's equation.

Mathematically, the Planck-Einstein equation can be calculated by using this formula:

E = hf

<u>Where:</u>

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In this scenario, this photon has an energy of 1.41 × 10⁻¹⁸ Joules because the electron dropped from an energy level i to the ground state by emitting a single photon.

Read more on photons here: brainly.com/question/9655595

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4 0
2 years ago
A car starts from rest and accelerates uniformly at a rate of 2.0 meter per second squared for 4.0 seconds. During this time int
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Answer:

16

Explanation:

\frac{1}{2}  \times 2 \times  {4}^{2}  = 16

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