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Semenov [28]
3 years ago
12

Show solution for # 4

Physics
1 answer:
velikii [3]3 years ago
7 0
M1 = 750Kg, v1 = 10m/s
m2 = 2500Kg , v2= 0 (because in problem say cuz that object don t move).

The momentum before colision is equal with the momentum after colision:

m1v1 + m2v2 = (m1+m2)v3 => v3 is the velocity after colison and that s u want to caluclate for your problem

=> m1v1 = (m1+m2)v3 => v3 = m1v1/(m1+m2) now u should do the math i think v3 prox 2,4 but not sure u should caculate
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1) Mass of one copper atom: 1.063\cdot 10^{-22} kg

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Explanation:

1)

We are told here that the mass of one mole of copper is

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We also know that the number of atoms inside 1 mole of substance is equal to Avogadro number:

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2)

We are told that the diameter of a copper atom is

d=2.28\cdot 10^{-10} m

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3)

The total mass of the cubical block of copper will be given by the mass of one atom of copper multiplied by the total number of atoms, so:

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N^3 = 9.33\cdot 10^{24} is the number of atoms in the cube

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Therefore, substituting, we find:

M=(9.33\cdot 10^{24})(1.063\cdot 10^{-22})=992 kg

So, the mass of the cubical block is 992 kg.

Learn more about mass and density:

brainly.com/question/5055270

brainly.com/question/8441651

#LearnwithBrainly

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