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DENIUS [597]
3 years ago
10

Energy transformations that occur when a ball is thrown in the air

Chemistry
1 answer:
Neporo4naja [7]3 years ago
4 0
Potential to kenetic energy
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Hydrogen gas
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3 0
3 years ago
Draw the products of the complete hydrolysis of an acetal. Draw all products of the reaction.
jolli1 [7]

Answer: the product is ketone or aldehyde

Explanation:

The first step is the conversion of acetal to hemiacetal in the presence of H3O+/ ROH, and then the final conversion of hemiacetal to ketone/aldehyde using

H3O+/ ROH...

Attached is the structural conversion

8 0
3 years ago
Predict the precipitate that forms when aqueous solutions of silver nitrate an potassium chloride react to form products in a do
Ket [755]
<span>you'll get silver chloride and potassium nitrate. Both of which are soluble, though so you get no precipitate

I thought all chlorides are soluble? </span>
5 0
3 years ago
Science / which phrase describes the differences between these two liquid ?
Zina [86]

Answer:

viscosity

Explanation:

one one left is mercury and the other one is honey right?

8 0
3 years ago
The standard molar heat of fusion of ice is 6020 j/mol. calculate q, w, and ∆e for melting 1.00 mol of ice at 0◦c and 1.00 atm p
zysi [14]

Answer :    q = 6020 J, w = -6020 J, Δe = 0

Solution : Given,

Molar heat of fusion of ice = 6020 J/mole

Number of moles = 1 mole

Pressure = 1 atm

Molar heat of fusion : It is defined as the amount of energy required to melt 1 mole of a substance at its melting point. There is no temperature change.

The relation between heat and molar heat of fusion is,

q=\Delta H_{fusion}(\frac{Mass}{\text{ Molar mass}})  (in terms of mass)

or, q=\Delta H_{fusion}\times Moles     (in terms of moles)

Now we have to calculate the value of q.

q=6020J/mole\times 1Mole=6020J

When temperature is constant then the system behaves isothermally and Δe is a temperature dependent variable.

So, the value of \Delta e=0

Now we have to calculate the value of w.

Formula used :    \Delta e=q+w

where, q is heat required, w is work done and \Delta e is internal energy.

Now put all the given values in above formula, we get

0=6020J+w

w = -6020 J

Therefore, q = 6020 J, w = -6020 J, Δe = 0

3 0
3 years ago
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