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3 years ago

HELPPPPPPPPPPPPPP

Mathematics

1 answer:

zvonat [6]3 years ago

8 0

Answer:

Step-by-step explanation:

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What’s the answer to

Roman55 [17]

Hint: the sum of the angles is equal to 180 in a triangle. could you make an equation to use that?

3x+13, 7x+2, and 75 are the three angle values. They will sum up to 180.

Steps:

We set the equation to:

3x+13+7x+2+75=180

We can combine some terms

10x+90=180

Then, we isolate x

10x=90

And we divide by 10

x=9

Great! but we are not done yet. We want the measure of angle A, so we need to plug x back into the equation for angle a

3(9)+13

Multiply

27+13

Add

8 0

2 years ago

Why does the shape of the moon appear to change over the course of about a month? (2 points)

kirill [66]

B. The sun is lighting up different amounts of the moon

5 0

2 years ago

9- 4(2p+3) - 8p+7<br> how do i solve this ?

Sholpan [36]

Answer:

$= -16p+4$

Step-by-step explanation:

First we simplify:

$9-4(2p+3)-8p+7$

Then we distribute:

$=9+(-4)(2p)+(-4)(3)+(-8p)+7\\=9+(-8p)+(-12)+(-8p)+7$

Lastly, combine like terms:

$=9+-8p+-12+-8p+7\\=(-8p+-8p)+(9+-12+7)\\=-16p+4$

Hope this helps!

Have a good evening! :)

7 0

3 years ago

Which of the values shown are potential roots of f(x) = 3x3 – 13x2 – 3x + 45? Select all that apply.

galina1969 [7]

Answer:

All potential roots are 3,3 and $-\frac{5}{3}$ .

Step-by-step explanation:

Potential roots of the polynomial is all possible roots of f(x).

$f(x)=3x^3-13x^2-3x+45$

Using rational root theorem test. We will find all the possible or potential roots of the polynomial.

p=All the positive/negative factors of 45

q=All the positive/negative factors of 3

$p=\pm 1,\pm 3,\pm 5\pm \pm 9,\pm 15\pm 45$

$q=\pm 1,\pm 3$

All possible roots

$\frac{p}{q}=\pm 1,\pm 3,\pm 5\pm \pm 9,\pm 15\pm 45,\pm \frac{1}{3},\pm \frac{5}{3}$

Now we check each rational root and see which are possible roots for given function.

$f(1)= 3\times 1^3-13\times 1^2-3\times 1+45\Rightarrow 32\neq 0$

$f(-1)= 3\times (-1)^3-13\times (-1)^2-3\times (-1)+45\Rightarrow \neq 32$

$f(-3)= 3\times (-3)^3-13\times (-3)^2-3\times (-3)+45\Rightarrow \neq -144$

$f(3)= 3\times (3)^3-13\times (3)^2-3\times (3)+45\Rightarrow =0\\\\ \therefore x=3\text{ Potential roots of function}$

Similarly, we will check for all value of p/q and we get

$f(-5/3)=0$

Thus, All potential roots are 3,3 and $-\frac{5}{3}$ .

5 0

3 years ago

Read 2 more answers

1. 350 is 70% of what number?

Brums [2.3K]

1. a
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3.b
4.c

msg me if u need explanations

4 0

4 years ago

Read 2 more answers