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Serga [27]
4 years ago
8

Determine the mass of oxygen necessary to react with 2.3 moles of HCl

Chemistry
1 answer:
Law Incorporation [45]4 years ago
3 0
Balanced equation:  4HCl + O₂  →  2Cl₂  +  2H₂O

mole ratio of HCl  :  O₂  is   4  :  1

∴ if moles of HCl = 2.3 mol

then mol of O₂ =  2.3 mol  ÷  4
                        = 0.575 mol

mass of O₂  =  moles of O₂ × molar mass of O₂
                    =  0.575 mol ×  (16 × 2) g/mol
                    =  18.4 g
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A(g) + 2B(g) → C(g) + D(g)
WITCHER [35]

Answer:

0.169

Explanation:

Let's consider the following reaction.

A(g) + 2B(g) ⇄ C(g) + D(g)

We can find the pressures at equilibrium using an ICE chart.

       A(g) + 2 B(g) ⇄ C(g) + D(g)

I       1.00     1.00        0        0

C       -x        -2x        +x       +x

E    1.00-x  1.00-2x     x         x

The pressure at equilibrium of C is 0.211 atm, so x = 0.211.

The pressures at equilibrium are:

pA = 1.00-x = 1.00-0.211 = 0.789 atm

pB = 1.00-2x = 1.00-2(0.211) = 0.578 atm

pC = x = 0.211 atm

pD = x = 0.211 atm

The pressure equilibrium constant (Kp) is:

Kp = pC × pD / pA × pB²

Kp = 0.211 × 0.211 / 0.789 × 0.578²

Kp = 0.169

6 0
3 years ago
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Answer:

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Explanation:

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