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Rufina [12.5K]
3 years ago
12

The radius of a niobium atom is 131 pm. how many niobium atoms would have to be laid side by side to span a distance of 2.40 mm

Physics
1 answer:
pochemuha3 years ago
7 0
First, we must know the following conversions:

1 pm = 10⁻¹² m
1 mm = 10⁻³ m

Therefore,
1 pm = 10⁻⁹ mm

The radius of the atom is 131 pm, which means that the span of one atom, the diameter, is 262 pm.

Number of atoms needed = distance to be covered / span of one atom
Number of atoms needed = 2.4 / 262 x 10⁻⁹
Number of atoms needed = 9.16 x 10⁷

9.16 x 10⁷ atoms of niobium will be needed
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$613,077

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3 years ago
what is the acceleration of a car that slows down from 60m/s to 40 m/s during a period of 10 seconds?
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