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3 years ago

14

If you pull on something to the right with a force of 50 N and I pull on the same object to the left with a force of 60 N, what

will happen?
The object will accelerate toward you
The object will accelerate toward me
The object will not accelerate at all
It is impossible to pull an object in two different directions

1 answer:

EleoNora [17]3 years ago

7 0

Nxxncnx. NMakalsllalakskdnd cxhcnmdnx

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It takes Desmond from 4:00 to 9:00 to swim 27 km. What is his speed?

Hatshy [7]

The formula for speed is distance÷time. The distance in this situation is 27km and the amount of time taken to cover that distance is 5 hours. Now, we substitute the values into an equation:
Speed = 27km/5h
Speed = 5.4km/h
Therefore, Desmond's speed is 5.4km/h.

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3 years ago

A 16 V battery does 1705 J of work transferring charge. How much charge is transferred? Answer in units of C.

vladimir1956 [14]

Answer:

Explanation:

Given

Voltage $V=16\ V$

Work done $W=1705\ J$

Work is Equivalent to energy

We know that Charge is given by

$Q=I\cdot t$

where I=current

t=time

Energy $E=P\times t$

P=power

P=V\times I

V=Voltage

I=current

Also Energy $E=V\cdot I\cdot t$

$I=\frac{E}{V\cdot t}$

Substitute the value of I in charge

$Q=\frac{E}{V\cdot t}\times t$

$Q=\frac{E}{V}$

$Q=\frac{1705}{16}$

$Q=106.56\ C$

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3 years ago

a satellite is revolving around the sun in a circular orbit with uniform velocity v. if the gravitational force suddenly disappe

cestrela7 [59]

Answer:

when gravitational force suddenly disappears, then only centrifugal force will be acting and velocity is tangential to the orbit and hence, the satellite will fly off tangentially with same velocity v.

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4 years ago

A particle passes through the point P=(−3,1,0)P=(−3,1,0) at time t=3t=3, moving with constant velocity v⃗ =⟨5,3,−2⟩v→=⟨5,3,−2⟩.

eimsori [14]

Answer:

The parametric equation for the position of the particle is $(-18+5t,-8+3t,6-2t)$ .

Explanation:

Given that,

The point is

$P=(-3,1,0)$

Time t = 3

Velocity $v=(5,3,-2)$

We need to calculate the parametric equation for the position of the particle

Using parametric equation for position

$r(t)=r_{0}+v(t)t$ ....(I)

at t = 3,

$P=r(t)$

Put the value into the formula

$(-3,1,0)=r_{0}+(5,3,-2)\times3$

$(-3,1,0)=r_{0}+(15,9,-6)$

$r_{0}=(-18,-8,6)$

Put the value of r₀ in equation (I)

$r(t)=(-18,-8,6)+(5,3,-2)t$

$r(t)=(-18+5t,-8+3t,6-2t)$

Hence, The parametric equation for the position of the particle is $(-18+5t,-8+3t,6-2t)$ .

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3 years ago

The interference of two sound waves of similar amplitude but slightly different frequencies produces a loud-soft-loud oscillatio

svetlana [45]

Answer:

the correct answer is d Beats

Explanation:

when two sound waves interfere time has different frequencies, the result is the sum of the waves is

y = 2A cos 2π (f₁-f₂)/2 cos 2π (f₁ + f₂)/2

where in this expression the first part represents the envelope and the second part represents the pulse or beatings of the wave.

When examining the correct answer is d Beats

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3 years ago