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Sladkaya [172]
3 years ago
14

18. A circuit contains a 10 ohm resistor, a 50 ohm resistor, and an 80 ohm resistor connected in parallel. If you test this circ

uit with a DMM, you should read a total resistance value
A. 0.13 ohms
B. 75 ohms
C. 140 ohms
D. 7.55 ohms
Physics
1 answer:
lutik1710 [3]3 years ago
4 0

The equivalent resistance is D) 7.55 \Omega

Explanation:

The equivalent resistance of n resistors in parallel is given by the equation:

\frac{1}{R}=\frac{1}{R_1}+\frac{1}{R_2}+...+\frac{1}{R_n}

For three resistors such as in this problem, the equation becomes

\frac{1}{R}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}

where we have the following:

R_1 = 10 \Omega is the resistance of the 1st resistor

R_2 = 50 \Omega is the resistance of the 2nd resistor

R_3 = 80 \Omega is the resistance of the 3rd resistor

Substituting, we find the equivalent resistance:

\frac{1}{R}=\frac{1}{10}+\frac{1}{50}+\frac{1}{80}=0.133 \Omega^{-1}

R=\frac{1}{0.133}=7.55 \Omega

Learn more about resistance:

brainly.com/question/2364338

brainly.com/question/12246020

#LearnwithBrainly

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To solve this problem it is necessary to apply the concepts related to the frequency in a spring, the conservation of energy and the total mechanical energy in the body (kinetic or potential as the case may be)

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Where,

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Replacing,

f = \frac{1}{2\pi} \sqrt{\frac{1700}{5.3}}

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PART B) To solve this section it is necessary to apply the concepts related to the conservation of energy both potential (simple harmonic) and kinetic in the spring.

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This expression is equivalent to,

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Replacing we have,

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Solving for A,

A^2 = \frac{5.3*1.7^2 +1700*(0.045)^2}{1700}

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PART C) Finally, the total mechanical energy is given by the equation

E = \frac{1}{2}kA^2

E=\frac{1}{2}1700*(0.105)^2

E= 9.3712 J

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3 years ago
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