5.1 m
Explanation:
Let's set the ground as our reference point. Let's also call the dropped ball to be ball #1 and its height above the ground at any time t is given by
(1)
where 10 represents its initial height or displacement of 10 m above the ground. At the same time, the displacement of the second ball with respect to the ground
is given by
(2)
At the instant the two balls collide, they will have the same displacement, therefore

or

Solving for t, we get

We can use either Eqn(1) or Eqn(2) to hind the height where they collide. Let's use Eqn(1):


Answer:
The age of the universe would be 9.9 billion years
Explanation:
We can calculate an estimate for the age of the Universe from Hubble's Law. Let's suppose the distance between two galaxies is D and the apparent velocity with which they are separating from each other is v. At some point, the galaxies were touching, and we can consider that time the moment of the Big Bang.
Thus, the time it has taken for the galaxies to reach their current separations is:

and from Hubble's Law:

Therefore:

With the given value for the Hubble's constant we have:

and thus,

The turns ratio is equal to the voltage ratio. Let n1 and n2 be the primary and secondary turns. Then
5850V/120V=n1/n2
48.75=2680/n2
n2=2680/48.75
n2=55
It condenses into liquid water.
Answer:
i honestly don't know
Explanation:
but can you help me with a question