Answer: in a quiet room or the library,
also you better summarize your geometry lessons and remember the formulas :P
Using systems of equations, we need to eliminate one variable to make it into a 1 variable equation either using elimination or substitution.
Equation 1: 4x - 5y = 18
Equation 2: 5x+y = 58
For equation 2, there is only one y which makes it easy to substitute. So subtract 5x from both sides of the equation to get
y = -5x+58
Then we know what y is in terms of x, so plug it into equation 1.
4x - 5(-5x+58) = 18
It is now an equation with only 1 variable, which we can solve.
Distribute the -5 to (-5x+58)
4x+25x-290 = 18
Combine like terms
29x-290 = 18
Add 290 to both sides
29x = 308
Divide both sides by 29 to isolate the x
x = 308/29 wow what an ugly number, but its alright
Plug in x to equation 2 to find what y is
5(308/29)+y = 58
1540/29+y = 58
Subtract 1540/29 from both sides
y = 142/29
The y value is 142/29
Answer:1 dollar each
Step-by-step explanation:
The correct solution is x=5,y=1
Ste<u>p-by-step explanation:</u>
Given the set of equations
4x-9y=11(1)
10x-9y=41(2)
we have to determine the values of x and y
solve this using elimination method
4x-9y=11(1)
10x-9y=41(2)
(2)-(1)
10x-4x-9y-(-9y)=41-11
10x-4x-0=30
6x=30
x=30/6
=5
substitute y in (1)
![4\times 5-9y=11\\20-9y=11\\9y=20-11=9\\y=9/9\\=1](https://tex.z-dn.net/?f=4%5Ctimes%205-9y%3D11%5C%5C20-9y%3D11%5C%5C9y%3D20-11%3D9%5C%5Cy%3D9%2F9%5C%5C%3D1)
x=5
y=1