Na₂C₂O₄(aq) + Pb(NO₃)₂⇒PbC₂O₄(s) + 2NaNO₃(aq)
<h3>Further explanation</h3>
Given
Word equation
Required
Balanced equation
Solution
Convert to skeleton equation
Na₂C₂O₄(aq) + Pb(NO₃)₂⇒PbC₂O₄(s) + NaNO₃(aq)
Balanced equation
Give a coefficient
Na₂C₂O₄(aq) + aPb(NO₃)₂⇒bPbC₂O₄(s) + cNaNO₃(aq)
Make an equation
C, left = 2, right =2b⇒2b=2⇒b=1
Na, left = 2, right = c⇒c=2
O, left = 4+6a, right = 4b+3c⇒4+6a=4b+3c⇒4+6a=4.1+3.2⇒6a=6⇒a=1
The equation becomes :
Na₂C₂O₄(aq) + Pb(NO₃)₂⇒PbC₂O₄(s) + 2NaNO₃(aq)
Answer:
≈29.94 [°C].
Explanation:
all the details are in the attachment, the answer is underlined with orange colour.
The Lewis structure the student drew is incorrect. The total number of electrons in bonds and lone pairs is equal to the total number of valence electrons available, then a valid Lewis structure is produced.
The correct structure is the following:
The structure that was drawn by the student was incorrect because the total number of electrons around Oxygen were incorrect, there were 6 instead of 8, which was against the octet rule. The correct structure should have 8 electrons around each atom.
Glucose is a monosaccharide
<h2>Answer:</h2>
Water (H2O) and Sodium (Na) are reactants.
<h2>Explanation:</h2>
2H2O+2Na......2NaOH+H2
In the above reaction the water (H2O) and sodium (Na) are reactants and sodium hydroxide (NaOH) and hydrogen are products.
And this is the single displacement reaction.