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3 years ago

Is a straight chain, a linear chain and an unbranched chain the same thing?

Chemistry

2 answers:

Minchanka [31]3 years ago

8 0

Answer:

All carbon atoms can be connected to a continuous chain in the straight-chain alkane. In alkanes of a branched-chain, all carbon atoms cannot be connected to a continuous chain as a branch or side chain is part of the carbon chain.

Explanation:

Schach [20]3 years ago

3 0

Answer:

In the straight-chain alkanes, each carbon is bound to its two neighbors and to two hydrogen atoms. (In red) Exceptions are the two terminal carbon nuclei, which are bound to only one carbon atom and three hydrogen atoms. (In blue)

Explanation:

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What is the volume of a gas at 756.14 Torr. If the volume was 588.56 mL at 588.56 torr.

creativ13 [48]

Answer:

Explanation:

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Calculate the Molarity when a 6.11 mL solution of 0.1 H2SO4 is diluted with 105.12 mL of water

barxatty [35]

Molarity after dilution : 0.0058 M

<h3>Further explanation </h3>

The number of moles before and after dilution is the same

The dilution formula

M₁V₁=M₂V₂

M₁ = Molarity of the solution before dilution

V₁ = volume of the solution before dilution

M₂ = Molarity of the solution after dilution

V₂ = Molarity volume of the solution after dilution

M₁=0.1 M

V₁=6.11

V₂=105.12

$\tt M_2=\dfrac{M_1.V_1}{V_2}=\dfrac{0.1\times 6.11}{105.12}=0.0058~M$

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3 years ago

If the mass of 23 gummi bears is 49.2g, what is the average mass of one gummi bear? Round answer to the nearest 0.00g (do NOT ty

Mila [183]

just divide the mass 49.2 grams by the amount of gummi bears 23 to get the answer of 2.1391 then it says to round to 2 decimals so 2.14 grams

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3 years ago

At 9 a.m. on May 21, a body is discovered near a path in a park. The body is 10 feet from a tree beside the path. The body is pa

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I'm pretty sure its D, Time of discovery of the body. Let me know (:

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3 years ago

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How can one tell how much of each reactant will be used in a reaction?

Ostrovityanka [42]

To Tell how much of each reactant will be used in a reaction, we need to find which reactant is the Limiting Reagent.
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