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olganol [36]
4 years ago
14

How many magnitude 8 earthquakes does it take to equal the energy release for a magnitude 9 earthquake?

Physics
1 answer:
WINSTONCH [101]4 years ago
8 0
The popular Richter scale for measuring the magnitude of earthquakes is based on a log₁₀ scale.
Therefore, a magnitude 9 earth quake is 10 times a magnitude 8  earthquake.

That is, it takes ten magnitude 8  earthquakes to equal the energy released by one magnitude 9 earthquake.

Answer: 10
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A car accelerates uniformly from rest to 20 m/sec in 5.6 sec along a level stretch of road. Ignoring friction, determine the ave
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The average power is defined as the amount of work done during a time interval:

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According to work-energy theorem, the work done is equal to the change in kinetic energy. So, we have:

W=\Delta K\\W=K_f-K_0\\W=\frac{mv_f^2}{2}-\frac{mv_0^2}{2}\\(2)

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W=\frac{wv_f^2}{2g}

(a) Finally, we replace this in (1):

P=\frac{wv_f^2}{2gt}\\P=\frac{9000N(20\frac{m}{s})^2}{2(9.8\frac{m}{s^2})(5.6s)}\\P=33000W

(b)

P=\frac{14000N(20\frac{m}{s})^2}{2(9.8\frac{m}{s^2})(5.6s)}\\P=51000W

3 0
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