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olganol [36]
4 years ago
14

How many magnitude 8 earthquakes does it take to equal the energy release for a magnitude 9 earthquake?

Physics
1 answer:
WINSTONCH [101]4 years ago
8 0
The popular Richter scale for measuring the magnitude of earthquakes is based on a log₁₀ scale.
Therefore, a magnitude 9 earth quake is 10 times a magnitude 8  earthquake.

That is, it takes ten magnitude 8  earthquakes to equal the energy released by one magnitude 9 earthquake.

Answer: 10
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Two timpani (tunable drums) are played at the same time. One is correctly tuned so that when it is struck, sound is produced tha
yKpoI14uk [10]

Answer:

Explanation:

Given

Wavelength of first timpani \lambda _1=2.2\ m

Frequency corresponding to this Wavelength

f_1=\frac{v}{\lambda _1}

where v=velocity\ of\ sound (343 m/s)

f_1=\frac{343}{2.2}

f_1=155.9\ Hz

Wavelength of Second timpani \lambda _2=2.1\ m

Frequency corresponding to this Wavelength

f_2=\frac{v}{\lambda _2}

f_2=\frac{343}{2.1}=163.33\ Hz

Beat frequency =f_2-f_1

Beat frequency =163.33-155.9=7.43

so approximately 7 beats per second

4 0
4 years ago
suppose that two objects attract each other with a gravitational force of 32 newtons. if the distance between the two objects is
grandymaker [24]

Taking into account the Universal Law of Gravitation, the force of attraction between the tow objects is 8 N.

<h3>Universal Law of Gravitation</h3>

The Universal Law of Gravitation establishes that bodies, by the simple fact of having mass, experience a force of attraction towards other bodies with mass, called gravitational force.

The Universal Law of Gravitation states that the gravitational force between two bodies is directly proportional to the product of their masses and inversely proportional to the square of the distance that separates them.

Mathematically it is expressed as follows:

F=G\frac{Mm}{d^{2} }

where:

  • G is the universal gravitational constant, with a value of 6.67×10⁻¹¹ \frac{Nm^{2} }{kg^{2} }.
  • M and m are the masses of the bodies that interact.
  • d is the distance that separates them.

<h3>Force of attraction in this case</h3>

In this case, two objects attract each other with a gravitational force of 32 newtons. The distance between the two objects is doubled.

Since gravitational force is inversely proportional to the square of the separation distance between the two interacting objects, more separation distance will result in weaker gravitational forces. So as two objects are separated from each other, the force of gravitational attraction between them also decreases.

Then, if the separation distance between two objects is doubled (increased by a factor of 2), then the force of gravitational attraction is decreased by a factor of 4 (d²= 2²= 4). The new force is then \frac{1}{4} of the original:

F=\frac{1}{4}×Foriginal

F=\frac{1}{4}×32 N

<u><em>F= 8 N</em></u>

Finally, the force of attraction between the tow objects is 8 N.

Learn more about the Universal Law of Gravitation:

brainly.com/question/15967105

brainly.com/question/11359658

#SPJ1

6 0
2 years ago
What is the velocity of a wave that has a wavelength of 20 meters and frequency of 0.5<br> Hz?
k0ka [10]

Answer:

v = 10 m/s

Explanation:

recall that velocity is related to wavelength and frequency by the formula

v = fλ

where v = velocity, f = frequency and λ= wavelength

Simply substitute these into the formula:

v = fλ

v = (0.5)(20)

v = 10 m/s

3 0
3 years ago
Read 2 more answers
A nonconducting sphere contains positive charge distributed uniformly throughout its volume. Which statements about the potentia
just olya [345]
This statement about the potential due to the sphere is correct: THE POTENTIAL IS HIGHEST AT THE CENTER OF THE SPHERE.
The potential is highest at the center of the sphere because, charge usually flow from the region of higher potential to lower potential.
7 0
4 years ago
A uniform solid disk and a uniform ring are place side by side at the top of a rough incline of height h.
nadezda [96]

Explanation:

velocity of disc =\sqrt((gh)/0.75)

lets call (h) 1 m to make it simple.

= 3.614 m/s

\sqrt((4/3) x 1 x 9.8) = 3.614 m/s pointing towards this:

4×V_d=\sqrt(4/3hg)

V_h=\sqrt(hg)

velocity of hoop=\sqrt(gh)

lets call (h) 1m to make it simple again.

\sqrt(9.8 x 1) = 3.13 m/s

\sqrt(gh) = sqrt(hg)so [tex]4×V_d= \sqrt(4/3hg)V_h=\sqrt(hg)

The disc is the fastest.

While i'm on this subject i'll show you this:

Solid ball =0.7v^2= gh

solid disc = 0.75v^2 = gh

hoop =v^2=gh

The above is simplified from linear KE + rotational KE, the radius or mass makes no difference to the above formula.

The solid ball will be the faster of the 3, like above i'll show you.

solid ball: velocity =\sqrt((gh)/0.7)

let (h) be 1m again to compare.

\sqrt((9.8 x 1)/0.7) = 3.741 m/s

solid disk speed =\sqrt((gh)/0.75)

uniform hoop speed =\sqrt(gh)

solid sphere speed =\sqrt((gh)/0.7)

8 0
3 years ago
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