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3 years ago

How many magnitude 8 earthquakes does it take to equal the energy release for a magnitude 9 earthquake?

1 answer:

8 0

The popular Richter scale for measuring the magnitude of earthquakes is based on a log₁₀ scale.
Therefore, a magnitude 9 earth quake is 10 times a magnitude 8 earthquake.

That is, it takes ten magnitude 8 earthquakes to equal the energy released by one magnitude 9 earthquake.

Answer: 10

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Question 2

ra1l [238]

Answer:

0.729 meters

Explanation:

d=(V0)t+(1/2)at^2

d=height of shelf

a=9.8 m/s^2 (acceleration due to gravity)

V0=0 m/s (initial downward velocity)

t=0.38586 seconds (1.173 meters/3.04 m/s)

4 0

2 years ago

A passenger jet flies from one airport to another 1293 miles away in 2.1hours . Find average speed

JulsSmile [24]

The average speed is 615.7 mph (275.2 m/s)

Explanation:

The average speed of an object gives a measure of how fast an object is moving over a certain time interval. It is a scalar quantity, and it is calculated as follows

$v=\frac{d}{t}$

where

v is the average speed

d is the distance covered

t is the time interval

For the jet in this problem, we have:

d = 1293 mi is the distance covered

t = 2.1 h is the time interval

Therefore, the average speed is:

$v=\frac{1293}{2.1}=615.7 mph$

We can also convert into SI units (m/s), keeping in mind that:

$1 mi = 1609 m\\1 h = 3600 s$

And so

$v=615.7 \frac{mi}{h}\cdot \frac{1609 m/mi}{3600 s/h}=275.2 m/s$

Learn more about average speed:

brainly.com/question/8893949

brainly.com/question/5063905

#LearnwithBrainly

6 0

3 years ago

How did the old view of the solar system look like

zhuklara [117]

The old view of the solar system was geocentric, which means that people believed that the Earth is the center of the universe. However, with the discoveries of Galileo, Newton, and Copernicus, evidence was brought forth that the solar system is actually heliocentric, which means that the sun is the center of the universe.

3 0

2 years ago

A moving walkway has a speed of .4 m/s to the east. A stationary observer sees a man walking on the walkway with a velocity of 3

SVEN [57.7K]

Explanation:

Vnet = 0.4m/s - 3.0m/s = - 2.6m/s

so the man walks 2.6m/s towards the west

8 0

3 years ago

What is the de Broglie wavelength for a proton with energy 50 keV? Due to the limitations of Canvas, please give the wavelength

ad-work [718]

Answer:

1.2826 x 10^-13 m

Explanation:

$\lambda = \frac{h}{\sqrt{2 m K}}$

Here, k be the kinetic energy and m be the mass

K = 50 KeV = 50 x 1.6 x 10^-16 J = 80 x 10^-16 J

m = 1.67 x 10^-27 kg

$\lambda = \frac{6.63 \times 10^{-34}}{\sqrt{2 \times 1.67\times 10^{-27}\times 80\times 10^{-16}}}$

λ = 1.2826 x 10^-13 m

6 0

2 years ago