Explanation:
neglecting air resistance both will land at the same moment.
both have therefore the same acceleration.
Answer:
Amplitude = 0.02m
Frequency = 640 Hz
Wavelength, λ = 0.5m
v = 320 m/s
Explanation:
Given the wave equation :
y=0.02 sin2π/0.5 (320t - x) where x and y are in
meters and t is in second
Comparing the above relation with the general wave equation :
y(x, t) = Asin2π/λ(wt - kx)
The amplitude, A = 0.02
From the equation :
2π/0.5 = 2π/λ
λ = 0.5 m
320t = vt
Hence, v = 320 m/s
Recall :
v = fλ
320 = f * 0.5
f = 320 / 0.5
f = 640 Hz
Blank is something empty lol
Answer:
λ = 548.7 nm
Explanation:
Hi!
First we want to know how much energy we need to remove 1 electron from the surface of the solid:
218.1 kJ/mol => 218 100 J / (6.022 x 10^23) electrons
= 3.621 x 10^-19 J/electron
That is we need 3.621 x 10^-19 J to remove one electron
Now we can calculate the wavelength that a photon must have in order to have this energy:
E = (hc) / λ
λ = (hc) / Ε
where
h = 6,626070150(69) ×10 -34 Js (wikipedia)
c = 3 x10^8 m/s
hc = 1.987 x 10^-25 Jm
Therefore:
λ = ( 1.987 x 10^-25 /3.621 x 10^-19 ) m = 5.487 x 10^-7 m
λ = 548.7 nm
The focal length would likely decrease as the refractive index and the increase when the curvature radius of the lens increases. The decrease in focal length happens since a higher index of refraction would signify that the rays of the sun striking to an object would tend to bend more.
