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ruslelena [56]
3 years ago
13

The joule (J) is a unit of energy. Recall that energy may be converted between many different forms such as mechanical energy, t

hermal energy (heat), chemical energy, electrical energy, and light.The mechanical energy produced by a system is called work. When work is accomplished through the changing volume of a gas, it is called PV work and is given by the formula w=−PΔV, where w is the work, P is the external pressure, and ΔV is the change in volume. If the volume change and pressure are in liters and atmospheres respectively, then the work will have units of liter-atmospheres, which can be converted to joules using the conversion factor 1 L⋅atm=101.3 J.Work can also be expressed as force multiplied by distance: w=F×d, where w is the work in joules, F is the force in newtons, and d is the distance in meters. Note that 1 N⋅m=1 J.

Physics
2 answers:
REY [17]3 years ago
7 0

Complete Question

The complete question is shown on the first uploaded image

Answer:

The workdone is  W = -177.275J

Explanation:

From the question we are told that

      The initial Volume is  Vi = 0.160 L

      The final volume is  V_f = 0.510L

      The external pressure is  P = 5.00 \ atm

Generally the change in volume is

           \Delta V = V_f - V_i

Substituting values we have

           \Delta V = 0.510 -0.160

                 = 0.350L

Generally workdone is mathematically represented as

           W = -P \Delta V

W is negative because the working is done on the environment by the system which is indicated by volume increase

     Substituting values

                W = - 5* 0.350

                    = -1.75 \ L \ \cdot atm

Now  1 \  L \cdot atm = 101.3J

  Therefore  W = -1.75* 101.3

                          = -177.275J

   

svetoff [14.1K]3 years ago
5 0

Answer:

Workdone = -1.75 L.atm = -177.275 J

Explanation:

Given,

External pressure = 5.00 atm

Initial volume = V(initial) = 0.160 L

Final volume = V(final) = 0.510 L

The piston acts against the constant external pressure of 5.00 atmospheres. The volume expands to 0.510 L from 0.160 L

W = -PΔV

P = 5.00 atm

ΔV = V(final) - V(initial) = 0.510 - 0.160 = 0.35 L

W = - 5 × 0.35 = - 1.75 L.atm

This work can then be expressed in Joules

1 L.atm = 101.3 J

-1.75 L.atm = -1.75 × 101.3 = -177.275 J

Note that the workdone is negative because the system does work on the environment in this expansion procase that led to increase in volume.

Hope this Helps!!!

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For a given amount of gas at a constant temperature, the volume of a gas varies inversely with its pressure is a statement of __
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Answer:

d. Boyle's

Explanation:

Boyle's Law: States that the volume of a fixed mass of gas is inversely proportional proportional to its pressure, provided temperature remains constant.

Stating this mathematically. this implies that:

V∝1/P

V = k/P, Where k is the constant of proportionality

PV = k

P₁V₁ = P₂V₂

Where P₁ and P₂ are the initial and final pressure respectively, V₁ and V₂ are the the initial and final volume respectively.

Hence the right option is d. Boyle's

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Explain three ways visual aids help you study
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Two forces of 50 N and 30N respectively, are acting on an object. Find the net force (in N) on the object if
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A) the forces are acting in the same direction.. B) Together, forces are acting in opposite directions

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A spring is hung from the ceiling. A 2.0-kg mass suspended hung from the spring extends it by 6.0 cm. A downward external force
Stolb23 [73]

The work done by force on a spring hung from the ceiling will be 1.67 J

Any two things with mass are drawn together by the gravitational pull. We refer to the gravitational force as attractive because it consistently seeks to draw masses together rather than pushing them apart.

Given that a spring is hung from the ceiling with a 2.0-kg mass suspended hung from the spring extends it by 6.0 cm and a downward external force applied to the mass extends the spring an additional 10 cm.

We need to find the work done by the force

Given mass is of 2 kg

So let,

F = 2 kg

x = 0.1 m

Stiffness of spring = k = F/x

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Now the formula to find the work done by force will be as follow:

Workdone = W = 0.5kx²

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W = 1.67 J

Hence the work done by force on a spring hung from the ceiling will be 1.67 J

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brainly.com/question/12970081

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