Answer:
Thus, the order of the reaction is 2.
The rate constant of the graph which is :- 2.00 M⁻¹s⁻¹
Explanation:
The kinetics of a reaction can be known graphically by plotting the concentration vs time experimental data on a sheet of graph.
The concentration vs time graph of zero order reactions is linear with negative slope.
The concentration vs time graph for a first order reactions is a exponential curve. For first order kinetics the graph between the natural logarithm of the concentration vs time comes out to be a straight graph with negative slope.
The concentration vs time graph for a second order reaction is a hyberbolic curve. Also, for second order kinetics the graph between the reciprocal of the concentration vs time comes out to be a straight graph with positive slope.
Considering the question,
A plot of 1/[NOBr] vs time give a straight line with a slope of 2.00 M⁻¹s⁻¹.
<u>Thus, the order of the reaction is 2.</u>
<u>Also, slope is the rate constant of the graph which is :- 2.00 M⁻¹s⁻¹</u>
Answer:
Bromine is found in Group 17, Period 4 on the periodic table.
27.7g
Explanation:
Given parameters:
Number of moles of oxygen = 3.15moles
Unknown:
Mass of reacting propane = ?
Solution:
Equation of the reaction:
C₃H₈ + 5O₂ → 3CO₂ + 4H₂O
We work from the known to the unknown parameters.
The known in this expression is the number of moles of oxygen.
In the reaction:
5 moles of oxygen gas reacts with 1 mole of propane
3.15 mole of oxgen gas will react with 
= 0.63moles
Number of moles of reacting propane gas is 0.63moles
To find the mass;
mass = number of moles x molar mass = 0.63 x molar mass
molar mass of propane = (3 x 12) + (8x1) = 44g/mol
mass of propane = 0.63 x 44 = 27.7g
Learn more:
Combustion reaction brainly.com/question/6126420
#learnwithBrainly
