Fireworks contain metals that are brightly colored when burned. They are less reactive than some other metals. Which metal is on
2 answers:
You might be interested in
<u>Answer:</u> The moles of precipitate (lead (II) iodide) produced is moles
<u>Explanation:</u>
To calculate the number of moles for given molarity, we use the equation:
.....(1)
- <u>For lead (II) nitrate:</u>
Molarity of lead (II) nitrate solution = 2.70 M
Volume of solution = 33.0 mL = 0.033 L (Conversion factor: 1 L = 1000 mL)
Putting values in equation 1, we get:
- <u>For NaI:</u>
Molarity of NaI solution = 0.00157 M
Volume of solution = 20.0 mL = 0.020 L
Putting values in equation 1, we get:
For the given chemical reaction:
By Stoichiometry of the reaction:
2 moles of NaI reacts with 1 mole of lead (II) nitrate
So, moles of NaI will react with =
of lead (II) nitrate
As, given amount of lead (II) nitrate is more than the required amount. So, it is considered as an excess reagent.
Thus, NaI is considered as a limiting reagent because it limits the formation of product.
By Stoichiometry of the reaction:
2 moles of NaI produces 1 mole of lead (II) iodide
So, moles of NaI will produce =
of lead (II) iodide
Hence, the moles of precipitate (lead (II) iodide) produced is moles