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Ket [755]
3 years ago
12

A water solution of sodium acetate is basic because...a. the conjugate base of the acetate ion is a strong base. b. sodium aceta

te is only weakly ionized. c. the acetate ion acts as a Bronsted-Lowry base in a reaction with water. d. A water solution of sodium acetate is acidic.
Chemistry
1 answer:
Novay_Z [31]3 years ago
5 0

Answer:

The correct answer is c. the acetate ion acts as a Bronsted-Lowry base in a reaction with water.

Explanation:

Sodium acetate (NaCH₃COO) dissociates in water to give Na⁺ and CH₃COO⁻ ions as follows:

NaCH₃COO(s) → Na⁺(aq) + CH₃COO⁻(aq)

The acetate ion (CH₃COO⁻) is the conjugated base of acetic acid (CH₃COOH). Acetic acid is a weak acid, so the acetate ion will try to regenerate the weak acid. For this, it will acept a proton (acting as a Bronsted-Lowry base) from water to form acetic acid. As result, OH⁻ is released and the solution turns basic:

CH₃COO⁻(aq) + H₂O(l) ⇄ CH₃COOH(aq) + OH⁻(aq)

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Why should you be careful when you heat your NaCl solution to evaporate the water?
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Answer & Explanation:

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At a given temperature the vapor pressure of pure liquid benzene and toluene are 745 torr and 290 torr, respectively. A solution
IRISSAK [1]

Answer:

Vapour pressure of benzene over the solution is 253 torr

Explanation:

According to Raoult's law for a mixture of two liquid component A and B-

vapour pressure of a component (A) in solution = x_{A}\times P_{A}^{0}

vapour pressure of a component (B) in solution = x_{B}\times P_{B}^{0}

Where x_{A},x_{B} are mole fraction of component A and B in solution respectively

P_{A}^{0},P_{B}^{0} are vapour pressure of pure A and pure B respectively

Here mole fraction of benzene in solution is 0.340 and vapour pressure of pure benzene is 745 torr

So, vapour pressure of benzene in solution = 0.340\times 745 torr

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3 years ago
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