The part of the atom that takes up the most space is the amount of electrons
Answer:
bruh
Explanation:
The purpose of this lab was to explore the different types of chemical reactions in this laboratory procedure. The question for this lab is, how does knowing the reactants and products help me classify a chemical reaction. In this experiment, I made observations of the reactants and the products. I used these observations to write the balanced chemical equations and to classify the reaction it made.
Answer:
The temperature of the system once the equilibrium has been reached = 372.55K
Explanation:
Heat capacity of gold = 129 J/Kg*c.
Heat capacity of water
4,184 J/Kg*c.
Mass of gold = 75g = 0.075Kg
Mass of water = 200g = 0.2Kg
From conservation of energy
m1×C1×(t11 - t2) = m2×C2×(t2- t21)
Substituting we have
0.075 × 129×(1000-t2) = 0.2× 4184×( t2 -300) =solving for t2, we have
933.55×t2 = 347790
or t2 = 372.55K
The temperature of the system once the equilibrium has been reached = 372.55K
Answer:
Avogadro's number is 1 mol = 6.02 * 10^23 elements
It means that 1 mol of atoms is 6.02 * 10^23 atoms
1 mol of atoms = 6.02 * 10^23 atoms
From there, if you divide both sides by 1 mol of atoms, you get
1 = 6.02 * 10^23 atoms / 1 mol of atoms.
That means, that to pass from a number of moles of atoms to number of atoms you have to multipby by the conversion factor
6.02*10^23 atoms Al/ 1 mol Al
That is the second option of the list.
Explanation:
Answer:
86.6 mL
Explanation:
From the question given above, the following data were obtained:
Initial volume (V₁) = 56.8 mL
Initial pressure (P₁) = 664 mmHg
Initial temperature (T₁) = 135 K
Final pressure (P₂) = 632 mmHg
Final temperature (T₂) = 196 K
Final volume (V₂) =?
The final volume of the gas can be obtained as follow:
P₁V₁/T₁ = P₂V₂/T₂
664 × 56.8 / 135 = 632 × V₂ / 196
Cross multiply
135 × 632 × V₂ = 664 × 56.8 × 196
85320 × V₂ = 7392179.2
Divide both side by 85320
V₂ = 7392179.2 / 85320
V₂ = 86.6 mL
Therefore, the final volume of the gas is 86.6 mL
