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STatiana [176]
3 years ago
11

A sample of neon gas at 1.20 atm compresses from 0.250 L to 0.125 L. If the temperature remains constant, what is the final pres

sure in atm?A. 0.600 atm B. 1.000 atm C. 1.20 atm D. 2.40 atm E. none of the above
Chemistry
1 answer:
laila [671]3 years ago
7 0

Answer:

D. 2.40 atm

Explanation:

At constant temperature and number of moles, using Boyle's law  

{P_1}\times {V_1}={P_2}\times {V_2}

Given ,  

V₁ = 0.250 L

V₂ = 0.125 L

P₁ = 1.20 atm

P₂ = ? atm

Using above equation as:

{P_1}\times {V_1}={P_2}\times {V_2}

{1.20\ atm}\times {0.250\ L}={P_2}\times {0.125\ L}

{P_2=\frac{{1.20}\times {0.250}}{0.125}\ atm

{P_2}=2.40 atm

Answer:- D. 2.40 atm

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