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Anestetic [448]
3 years ago
5

Hunter wants to measure the weight of a dumbbell. He should

Chemistry
1 answer:
Elina [12.6K]3 years ago
8 0

Hunter wants to measure the weight of a dumbbell. He should use a scale and record the weight in N.

Answer: Option D

<u>Explanation:</u>

The weight of an object refers the gravity force it affects, and this can be indicated as the mass multiplied by the acceleration due to gravity force, w = mg. Because weight is the force and so the unit is Newton. When you are not on weight, the net force on the scale and on the ground is zero, and the scale value (and normal strength) corresponds to the weight of the system. When you stand on the scale and raise or lower the bar, the center of gravity of the system rises and falls much more than the weight compresses or expands.

Therefore, the scale power (power) must be increased or decreased (the ground is solid) so that the center of gravity can move, raise and lower. When the center of gravity begins to move at a constant speed, the scale force decreases, matching the weight of the system. If you start to slow down and stop the dumbbell movement, the balance will change the weight again until you stop it. Hence, option D would be the right choice.

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The balanced molecular chemical equation for the reaction will be expressed as Cs₂CO₃ + Mg(NO₃)₂ -> 2CsNO₃ + MgCO₃

  • For any chemical equation to be balanced, the number of moles of elements in the reactants must be equal to that of the product.

  • According to the question, we are to write a balanced equation for the reaction  in aqueous solution for cesium carbonate and magnesium  nitrate
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Hence the balanced molecular chemical equation for the reaction will be expressed as Cs₂CO₃ + Mg(NO₃)₂ -> 2CsNO₃ + MgCO₃

Learn more here: brainly.com/question/11904811

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You have 4 moles of oxygen gas in a flask. 4 moles of helium gas is added. What happens to the total pressure of the gases in th
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Answer: The correct option is (c). The total pressure doubles.

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Initially,  only 4 moles of oxygen gas were present in the flask.

p_{O_2}=Tp_1\times X_{O_2}  (X_{O_2}=\frac{4}{4}) ( according to Dalton's law of partial pressure)

p_{O_2}=Tp_1\times 1=Tp_1....(1)

Tp_1= Total pressure when only oxygen gas was present.

Final total pressure when 4 moles of helium gas were added:

X'_{O_2}=\frac{4}{8}=\farc{1}{2},X_{He}=\frac{4}{8}=\frac{1}{2}

partial pressure of oxygen in the mixture :

Since, the number of moles of oxygen remains the same, the partial pressure of oxygen will also remain the same in the mixture.

p_{O_2}=Tp_2\times X'_{O_2}=Tp_2\times \frac{1}{2}

Tp_2= Total pressure of the mixture.

from (1)

Tp_1=Tp_2\times X'_{O_2}=Tp_2\times \frac{1}{2}

On rearranging, we get:

Tp_2=2\times Tp_1

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