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Luba_88 [7]
4 years ago
11

when the c4 key on a piano keyboard is pressed, a string inside the piano is struck by a hammer and begins vibrating back and fo

rth at approximately 260 cycles per second. what is the frequency in hertz of the sound wave
Physics
2 answers:
Ugo [173]4 years ago
7 0
The correct answer is f= 260 Hz
svetlana [45]4 years ago
5 0

Answer:

260 Hz

Explanation:

The frequency of a sound wave is  defined as the number of oscillation which is given in cycles per time. Frequency (f) is given  by the formula ;

f = \frac{1}{T} and it is measured in Hertz(Hz)

Given that;

a vibration is caused by a struck string in piano at  260 cycles and Time (T) = 1 seconds

Frequency (f) can be determined as; 260 cycles × 1 seconds

= 260 Hertz (Hz)

Hence, the frequency of the sound wave is 260 Hertz (Hz).

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What is the mass of a person who weighs 653 N at earths surface
miss Akunina [59]

Answer:

66.6 kg

Explanation:

The weight of a person at Earth's surface is given by

W=mg

where

m is the mass of the person

g=9.8 m/s^2 is the acceleration of gravity

The person in the problem has a weight of

W = 653 N

Therefore, we can rearrange the equation to find his mass:

m=\frac{W}{g}=\frac{653}{9.8}=66.6 kg

7 0
4 years ago
A physics book slides off a table at 1.25ms and hits the ground after 0.4s
tresset_1 [31]

Answer:

Whats the question here?

7 0
3 years ago
A 140 kg load is attached to a crane, which moves the load vertically. Calculate the tension in the
Nesterboy [21]

Answer:

A.) 1372 N

B.) 1316 N

C.) 1428 N

Explanation:

Given that a 140 kg load is attached to a crane, which moves the load vertically. Calculate the tension in the cable for the following cases:

a. The load moves downward at a constant velocity

At constant velocity, acceleration = 0

T - mg = ma

T - mg = 0

T = mg

T = 140 × 9.8

T = 1372N

b. The load accelerates downward at a rate 0.4 m/s??

Mg - T = ma

140 × 9.8 - T = 140 × 0.4

1372 - T = 56

-T = 56 - 1372

- T = - 1316

T = 1316N

C. The load accelerates upward at a rate 0.4 m/s??

T - mg = ma

T - 140 × 9.8 = 140 × 0.4

T - 1372 = 56

T = 56 + 1372

T = 1428N

8 0
4 years ago
Plssss help Do you guys have any other more interesting, funny or creative ideas of incline problems than something sliding down
VashaNatasha [74]
U can always just do the classic roller coaster going up an incline and create some sort of story from that.
8 0
3 years ago
Light of wavelength 648.0 nm is incident on a narrow slit. The diffraction pattern is viewed on a screen 57.5 cm from the slit.
boyakko [2]

Answer:

71.0 \mu m

Explanation:

The formula for the single-slit diffraction is

y=\frac{n\lambda D}{d}

where

y is the distance of the n-minimum from the centre of the diffraction pattern

D is the distance of the screen from the slit

d is the width of the slit

\lambda is the wavelength of the light

In this problem,

\lambda=648.0 nm=6.48\cdot 10^{-7}m

D=57.5 cm=0.575 m

y=1.05 cm=0.0105 m, with n=2 (this is the distance of the 2nd-order minimum from the central maximum)

Solving the formula for d, we find:

d=\frac{n\lambda D}{y}=\frac{2(6.48\cdot 10^{-7} m)(0.575 m)}{0.0105 m}=7.10\cdot 10^{-5} m= 71.0 \mu m

6 0
3 years ago
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