Which of the following is not a triangle congruence theorem? ASA AAS SSA
1 answer:
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Answer:
about 5.613 seconds
Step-by-step explanation:
Using the quadratic formula to find the value of t when h = 0, we have ...
at² +bt +c = 0
t = (-b±√(b²-4ac))/(2a)
t = (-72±√(72² -4(-16)(100)))/(2(-16))
t = (-72±√11584)/-32 = (9±√181)/4
Only the positive value of t is of interest.
The coin will hit the stream after (9+√181)/4 seconds ≈ 5.613 seconds.
Step-by-step explanation:
Erase the dot points you already have. We are supposed to substitute those values in the right side of problem 1 into the function as x.
For example if x=-4
If x=-2
If x=0
So our point should be
-4,9
-2,7
0,5
-2,3
-4,1.
The range is all possible y values in a function. Since this is discrete and we are given the domain, our range will just be the y value of the points you graphed.
(9,7,5,3,1)