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Artemon [7]
3 years ago
8

Calculate the molality of 75.0 grams of MgCl2 (molar mass=95.21 g/mol) dissolved in 500.0 g of solvent.

Chemistry
2 answers:
nordsb [41]3 years ago
5 0

<u>Answer:</u> The molality of magnesium chloride is 1.58 m

<u>Explanation:</u>

To calculate the molality of solution, we use the equation:

\text{Molality}=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}

Where,

m_{solute} = Given mass of solute (magnesium chloride) = 75.0

M_{solute} = Molar mass of solute (magnesium chloride) = 95.21 g/mol  

W_{solvent} = Mass of solvent = 500.0 g

Putting values in above equation, we get:

\text{Molality of }MgCl_2=\frac{75.0\times 1000}{95.21\times 500.0}\\\\\text{Molality of }MgCl_2=1.58m

Hence, the molality of magnesium chloride is 1.58 m

Arada [10]3 years ago
4 0

Answer: C) 1.58 m

The molar mass of MgCl2 = 95.2g/mol.

UsaTestPrep

75.0g

95.2

g

mol

= 0.788mol

Explanation:

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What is the molarity of a solution that contains 0.400 mol HCl in 9.79 l solution?
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  • Option B, 0.0409 M

Explanation:

<u>1) Data:</u>

a) M = ?

b) n = 0.400 mol

V = 9.79 liters

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  • M = n / V (in liters)

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