1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
maksim [4K]
3 years ago
5

A student performs an experiment to find the percentage of water in a hydrate. He determines that the hydrate contains 22% water

, but the teacher tells him that it actually contains 40% water. What error may have caused him to obtain this low value?
Chemistry
1 answer:
Stels [109]3 years ago
4 0

Answer:

A feasible error could have been the removal of the sample before all water evaporated.

Explanation:

In order to determine the percentage of water in an hydrate, an experiment that could be performed is the heating of the sample until the mass does not change. If the student heated the sample an insufficient amount of time, water will be present in the sample, thus reducing the percentage reported.

You might be interested in
Ductile means...
balu736 [363]

Answer:

A

Explanation:

3 0
2 years ago
Can someone help me sort this :(
jeyben [28]

Answer: A. is prey B. is predator C. is habitat D. is comunity E. is plants are producers and plant eating animals  consumors  F. is food chain G. is food web H. parasite I decomposers and scavengers J. is compete K an adsption

Explanation:

7 0
2 years ago
A chemist adds 485 mL of a 0.0025 mol/L calcium sulfate solution to a reaction flask. Calculate the mass in grams of calcium sul
viva [34]

Answer : The mass in grams of calcium sulfate is 0.16 grams.

Explanation :

Molarity : It is defined as the number of moles of solute present in one litre of solution.

Formula used :

Molarity=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution}}

Solute is, CaSO_4

Given:

Molarity of CaSO_4 = 0.0025 mol/L

Molar mass of CaSO_4 = 136 g/mole

Volume of solution = 485 mL

Now put all the given values in the above formula, we get:

0.0025=\frac{\text{Mass of }CaSO_4\times 1000}{136\times 485}

\text{Mass of }CaSO_4=0.16g

Thus, the mass in grams of calcium sulfate is 0.16 grams.

6 0
3 years ago
Explain why each mineral has its own properties, different from every other mineral
kaheart [24]
Each mineral has its own properties different from other minerals because minerals are made up of different elements. Different elements which can be found on the periodic table all have unique properties, therefore, gold will have distinct properties in comparison with zinc or aluminium for example because they are made up of different elements :))))
I hope this is helpful
have a nice day
4 0
3 years ago
Which of the following shows the conservation of mass during cellular respiration? 3 CO2 3 H2O energy → 3 C6H12O6 3 O2 6 CO2 6 H
Thepotemich [5.8K]

The reaction that has been, following the law of conservation of mass has been \rm C_6H_1_2O_6\;+\;6\;O_2\;\rightarrow\;6\;CO_2\;+\;6\;H_2O\;+\;Energy.

The law of conservation has been given in the chemical reaction that there has been no loss or gain of the mass and energy.

The law of conservation has been evident when there has been an equal number of atoms of each element on the product and the reactant side.

<h3 /><h3>Conservation of mass in Cellular respiration</h3>

The following reactions have been identified as:

  • \rm 3\;CO_2\;+\;3\;H_2O\;+\;Energy\;\rightarrow\;3\;C_6H_1_2O_6

Carbon atoms

Reactant = 3

Product = 18

Oxygen atoms

Reactant = 9

Product = 18

Hydrogen atoms

Reactant = 6

Product = 36

The number of atoms is not equal on the product and reactant side, thus not follows the law of conservation of mass.

  • \rm 3\;O_2\;+\;6\;CO_2\;+\;6\;H_2O\;+\;Energy\;\rightarrow\;C_6H_1_2O_6\;+\;6\;O_2

Carbon atoms

Reactant = 6

Product = 6

Oxygen atoms

Reactant = 24

Product = 18

Hydrogen atoms

Reactant = 12

Product = 12

The number of atoms is not equal on the product and reactant side, thus not follows the law of conservation of mass.

  • \rm C_6H_1_2O_6\;+\;6\;O_2\;\rightarrow\;6\;CO_2\;+\;6\;H_2O\;+\;Energy

Carbon atoms

Reactant = 6

Product = 6

Oxygen atoms

Reactant = 18

Product = 18

Hydrogen atoms

Reactant = 12

Product = 12

The number of atoms is equal on the product and reactant side, thus follows the law of conservation of mass.

  • \rm 6\;H_2O\;+\;C_6H_1_2O_6\;\rightarrow\;6\;O_2\;+\;Energy

Carbon atoms

Reactant = 6

Product = 0

Oxygen atoms

Reactant = 12

Product = 12

Hydrogen atoms

Reactant = 24

Product = 0

The number of atoms is not equal on the product and reactant side, thus not follows the law of conservation of mass.

Thus, the reaction that has been following the law of conservation of mass has been \rm C_6H_1_2O_6\;+\;6\;O_2\;\rightarrow\;6\;CO_2\;+\;6\;H_2O\;+\;Energy.

Learn more about law of conservation, here:

brainly.com/question/2175724

4 0
2 years ago
Other questions:
  • All of the following describe work being done except:
    14·1 answer
  • An enzyme can catalyze a reaction with either of two substrates, S1 or S2. The Km for S1 was found to be 2.0 mM, and the Km, for
    9·1 answer
  • #1: Which type of substance is an electron-pair donor?
    8·1 answer
  • Calculate the Mass of water needed to make 20% solution from 50g of glucose ?
    5·1 answer
  • Nyatakan tiga aktiviti kerja yang melibatkan<br>proses pengurusan projek reka bentuk.​
    9·2 answers
  • What is the charge on an electron?
    14·1 answer
  • Ill give brainlist if you get it righttt...Radiant energy travels in the form of electromagnetic waves. Which statement describe
    10·1 answer
  • If you have 5.22*1022 molecules of glucose (C6H12O6) how many grams is this?
    12·1 answer
  • 1. If 3.2 L of nitrogen monoxide and 4.3 g of oxygen gas are combined, what volume of nitrogen dioxide will be formed? 2NO + 0,
    11·1 answer
  • How much kinetic energy does a 2kg object have if it is traveling at a velocity of 2m/s?
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!