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3 years ago

Anyone do the Algebra 2 unit 1 test on edg?

Mathematics

1 answer:

photoshop1234 [79]3 years ago

6 0

Step-by-step explanation:

no not me .. I'm doing math unit test

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If a car travels at a constant speed of 45km/hr how long will a journey of 270km take?<br><br>

dem82 [27]

Answer:

I think the answer is "6" but I could be wrong.

6 0

3 years ago

Read 2 more answers

PQR are points on a circle a tangent to the circle RT is also shown. what size is angle x give a reason for your answer

jeyben [28]

Answer:

x = 60

Step-by-step explanation:

The angle between a tangent and a chord is equal to the angle in the alternate segment, that is

x = ∠ PQR = 60°

5 0

3 years ago

Part of the population of 7000 oak in a wildlife preserve is infected with a parasite. A random sample of 50 elk shows that four

lbvjy [14]

Answer:

Answer is 560

Refer below.

Step-by-step explanation:

4/50=x/7000

50x=28000

X=560

7 0

3 years ago

What is the following product?

KiRa [710]

ANSWER

$2 \sqrt{42} +7 \sqrt{2}- 6- \sqrt{21}$

EXPLANATION

The given product is:

$( \sqrt{14} - \sqrt{3} )( \sqrt{12} + \sqrt{7} )$

We expand using the distributive property to obtain:

$\sqrt{14}( \sqrt{12} + \sqrt{7}) -\sqrt{3}( \sqrt{12} + \sqrt{7} )$

Extract the perfect squares to get:

$\sqrt{14}(2 \sqrt{3} + \sqrt{7}) -\sqrt{3}( 2\sqrt{3} + \sqrt{7} )$

Expand further to get;

$2 \sqrt{42} +7 \sqrt{2}- 2(3) - \sqrt{21}$

This simplifies to,

$2 \sqrt{42} +7 \sqrt{2}- 6- \sqrt{21}$

5 0

3 years ago

Precal : Note: Triangle may not be drawn to scale. Suppose a = 3 and A = 15 degrees

drek231 [11]

Given:

In a right triangle at B,

$\begin{gathered} a=3 \\ A=15^{\circ} \end{gathered}$

To find:

The length of the sides b and c and angle B.

Explanation:

Using the trigonometric ratio,

$\begin{gathered} sinA=\frac{a}{c} \\ \sin15^{\circ}=\frac{3}{c} \\ c=\frac{3}{\sin15^{\circ}} \\ c=11.59 \\ c\approx11.6 \end{gathered}$

Using the trigonometric ratio,

$\begin{gathered} \tan A=\frac{a}{b} \\ \tan15^{\circ}=\frac{3}{b} \\ b=\frac{3}{\tan15^{\circ}} \\ b=11.19 \\ b\approx11.2 \end{gathered}$

Using the angle sum property,

The angle B becomes,

$\begin{gathered} 90+15+B=180 \\ B=180-90-15 \\ B=75^{\circ} \end{gathered}$

Final answer:

The values are,

$\begin{gathered} b=11.2 \\ c=11.6 \\ B=75^{\circ} \end{gathered}$

3 0

1 year ago