Answer:
For any cross between Homozygous dominant and Homozygous recessive individual the offspring will always be 100% Heterozygous dominant, that is all will have Rr.
Explanation:
2. CO
3.O2
4.NH3
5.NO
6.NO2
7.CO2
8.H2
Answer:
65.4 is the mass for 1.9×10²⁴ atomsof Pb
Explanation:
1mol of atoms of Pb has → NA (6.02×10²³ atoms) and weighs → 207.2 g
Therefore 1.9×10²⁴ atomsof Pb may weigh (1.9×10²⁴ . 207.2) / NA = 65.4 g
Explanation:
Mitosis and Meiosis are forms of cell division. They use the same steps for cell division which are Prophase, Metaphase, Anaphase and Telophase.
Mitosis produces 2 diploid cells while Meiosis produces 4 haploid cells.
Meiosis stages -
- Interphase
- Prophase I
- Metaphase I
- Anaphase I
- Telophase I
- Prophase II
- Metaphase II
- Anaphase II
- Telophase II
- Cytokineses
Mitosis stages
- Prophase
- Prometaphase
- Metaphase
- Telophase
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For the first equation, we know that the Be gained a proton and became B. In order to cancel this out, we would need a
particle. This particle is also called a beta particle.
For the second equation, we know that Si gained a proton and became P. The particle for this equation would also be a beta particle (

), as the same thing is happening as in the first equation.
For the third equation, we know that some atom plus an alpha particle gives us platinum-192. By subtracting the 4 and 2 from the alpha particle, we get the missing atom to be

, or osmium-188.
For the last equation, we can simply add the mathematical value of the beta particle to the aluminum-28. This gives us a changed proton number, but not atomic mass with the missing atom being

, or magnesium-28.
Hope this helps!