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3 years ago

8

What is the strongest interparticle force in a sample of kr?

1 answer:

Anit [1.1K]3 years ago

7 0

Answer:
London Dispersion Force<span> is the strongest interparticle force in a sample of Kr.

Explanation:
Krypton belongs to Noble Gases. They exists in monoatomic form as they are inert in nature and are very less reactive. So, as there is no polarity in Krypton so it will fail to create either Dipole-Dipole or Hydrogen Bond Interactions between its atoms. While, London Dispersion Forces or Van Der Waals forces can exist between Kr atoms. When Kr atoms approaches one other they create Instantaneous dipole. This</span> Instantaneous dipole induces dipole in second Kr atom and the process starts propagating. Hence, interactions are generated between Kr atoms.

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A tank contains 90 kg of salt and 2000 L of water. Pure water enters a tank at the rate 6 L/min. The solution is mixed and drain

sashaice [31]

Answer:

a) 90 kg

b) 68.4 kg

c) 0 kg/L

Explanation:

Mass balance:

$-w=\frac{dm}{dt}$

w is the mass flow

m is the mass of salt

$-v*C=\frac{dm}{dt}$

v is the volume flow

C is the concentration

$C=\frac{m}{V+(6-3)*L/min*t}$

$-v*\frac{m}{V+(6-3)*L/min*t}=\frac{dm}{dt}$

$-3*L/min*\frac{m}{2000L+(3)*L/min*t}=\frac{dm}{dt}$

$-3*L/min*\frac{dt}{2000L+(3)*L/min*t}=\frac{dm}{m}$

$-3*L/min*\int_{0}^{t}\frac{dt}{2000L+(3)*L/min*t}=\int_{90kg}^{m}\frac{dm}{m}$

$-[ln(2000L+3*L/min*t)-ln(2000L)]=ln(m)-ln(90kg)$

$-ln[(2000L+3*L/min*t)/2000L]=ln(m/90kg)$

$m=90kg*[2000L/(2000L+3*L/min*t)]$

a) Initially: t=0

$m=90kg*[2000L/(2000L+3*L/min*0)]=90kg$

b) t=210 min (3.5 hr)

$m=90kg*[2000L/(2000L+3*L/min*210min)]=68.4kg$

c) If time trends to infinity the division trends to 0 and, therefore, m trends to 0. So, the concentration at infinit time is 0 kg/L.

6 0

3 years ago

3. How many moles are 1.707 x 10^24 atoms of carbon?

Paraphin [41]

Answer:

2.835 moles of carbon

Explanation:

By definition, there are 6.022x10^23 atoms (or compounds) in one mole.

Write and use this as a conversion factor:

(6.022x10^23 atoms)/mole

(1.707 x 10^24 atoms of carbon)/((6.022x10^23 atoms)/mole) = 2.835 moles carbon

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2 years ago

What is the percent composition by mass for hydrogen in water (H2O)?

saw5 [17]

Explanation:

Percentage composition = 2/18 = 11.11%.

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3 years ago

2. Convert 340,000 to scientific notation

arlik [135]

Answer:

3.4 x 10^5

Explanation:

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Slav-nsk [51]

Answer:

Prevent any European country from growing much stronger than its neighbors.

Explanation:

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