Answer:
The simplified version of
is
.
Step-by-step explanation:
The given expression is
![\sqrt[3]{135}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B135%7D)
According to the property of radical expression.
![\sqrt[n]{x}=(x)^{\frac{1}{n}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%7D%3D%28x%29%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D)
Using this property we get
![\sqrt[3]{135}=(135)^{\frac{1}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B135%7D%3D%28135%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)
![\sqrt[3]{135}=(27\times 5)^{\frac{1}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B135%7D%3D%2827%5Ctimes%205%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)
![\sqrt[3]{135}=(3^3\times 5)^{\frac{1}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B135%7D%3D%283%5E3%5Ctimes%205%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)
![[\because (ab)^x=a^xb^x]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%28ab%29%5Ex%3Da%5Exb%5Ex%5D)
![[\because \sqrt[n]{x}=(x)^{\frac{1}{n}}]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Csqrt%5Bn%5D%7Bx%7D%3D%28x%29%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D%5D)
![\sqrt[3]{135}=3\sqrt[3]{5}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B135%7D%3D3%5Csqrt%5B3%5D%7B5%7D)
Therefore the simplified version of
is
.
Answer:
Yes because sum of 2 line segment is greater than the third side
Step-by-step explanation:
Answer:
1500$ = 5.3
so she spent 56 hours
Step-by-step explanation:
x² - x - 6 = (x +3)(x - 2)
x² - 5x + 6 = (x - 2)(x - 3)
What is their common factor?
Answer: B. x - 2
Hello,
First we work out the equations:
x + y =62 will be the first equation.
2x= y +13 is the second equation.
We can first rewrite the second equation as 2x – y =13.
So we have:
x + y = 62
2x –y =13
KEEP IN MIND: With y being positive in one of the equations and negative in the other, we can combine the equations to quickly eliminate y and solve for x.
x + y = 62
+2x –y =13
3x = 75 divide both sides by 3 to get x.
x = 25
Now that we have x we can substitute the value for x, 25.
25 + y = 62 we can subtract 25 from both sides to get y.
y = 62- 25
y = 37
2(25) = 37 + 13
Therefore,
50 = 50
Have a amazing day.